PCl5(s) + H2O(g) ⇄ 2HCl (g) + POCl3 (g) Keq= 11 At equilibrium the 4.0L flask contains the indicated amounts of the three chemicals. PCl5 = 0.012 mol, H2O = 0.016 mol, HCl = 0.120 mol Calculate [POCl3].

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Q: Why is the answer 28? can someone show me the steps for solving this.

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