### Moment of Inertia Problem #### Diagram Explanation: The diagram represents a system with three masses (represented as red circles labeled M) connected by rigid, massless rods. The system is structured in a triangular arrangement, with the vertices labeled M and connected by blue lines. - The two vertical black lines represent axis #1 and axis #2. - The distance between axis #1 and axis #2 is given as \(0.3 \, \text{m}\). - The system includes a point labeled \(R\) between the vertical lines. #### Problem Statement: An object consists of balls and rigid (massless) rods as shown above. The distance between axis 1 and axis 2 is \(0.3 \, \text{m}\). - All three of the balls have a mass of \(2 \, \text{kg}\). **Questions:** 1. What is the moment of inertia about axis #1? - Answer field: \(\_\_\_\_\_ \, \text{kg m}^2\) - Number of attempts: Tries 0/2 2. What is the moment of inertia about axis #2? - Answer field: \(\_\_\_\_\_ \, \text{kg m}^2\) This exercise is about calculating the moment of inertia for a given system of masses and understanding how the distribution of mass affects rotational motion about different axes.

The moment of inertia of an object about an axis is given by the formula $I=m{l}^2$  ,where m is the mass of the object and l is the distance of the object from the axis of rotation.

In axis 1 , there are two objects lying on the considered axis of rotation , for which the distance from the axis of rotation to the object will be zero. In axis 2 , only one object is lying on the axis .

The height of an equilateral triangle with side a is given by the formula $h=\frac{\sqrt{3}a}{2}$, so the value of each side of the triangle will be $a=\frac{2h}{\sqrt{3}}$.