Please explain this 1,2, and 3 Consider following cache elements Cache can hold 64 kB Data are transferred between main memory and the cache in blocks of 16 bytes each Main memory consists of 16 MB For the hexadecimal main memory address 987654, show the following information (in hexadecimal format) 1.Tag, Line, and Offset(word) values for Direct-mapped Cache 2.Tag and Offset(Word) values for Associative Cache 3.Tag, Set, and Offset(word) values for aa 4-way Set-associative Cache

Please explain this 1,2, and 3 Consider following cache elements Cache can hold 64 kB Data are transferred between main memory and the cache in blocks of 16 bytes each Main memory consists of 16 MB For the hexadecimal main memory address 987654, show the following information (in hexadecimal format) 1.Tag, Line, and Offset(word) values for Direct-mapped Cache 2.Tag and Offset(Word) values for Associative Cache 3.Tag, Set, and Offset(word) values for aa 4-way Set-associative Cache

Management Of Information Security

6th Edition

ISBN:9781337405713

Author:WHITMAN, Michael.

Publisher:WHITMAN, Michael.

Chapter12: Protection Mechanisms

Section: Chapter Questions

Problem 6RQ

See similar textbooks

Similar questions

A cache is organized as a 4 way set associative cache Each set's cache line consists of 4 words (meaning there are 16 bytes per line, for each set of the cache). Each set individually has one Valid bit, and one Dirty bit, for each line. The tag field of this cache is 8 bits wide. The address is 32 bits wide. Question 1a) What is the number of cache lines? Question 1b) What is the total number of 'memory bitcells' that are needed to design this cache (note, this includes the bitcells required for the tags, valid and dirty bits).
The ability to freely associate data items is the primary characteristic that distinguishes a fully associative cache from a directly mapped cache. This ability is the major distinction between the two types of caches.
For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache: Tag Index Offset 31-10 9-6 5-0 1. What is the cache block size (in words)? 2. How many entries does the cache have? 3. What is the ratio between total bits required for such a cache implementation over the data storage bits?
How many total bits are required for a direct-mapped cache with 2^12 blocks (12-bit index), two-word in each block, assuming 64-bit address? Compare this total cache size with the 2^13 words for storage of data as given above.
For a direct-mapped cache design with a 32-bit address, the following bits ofthe address are used to access the cache. We assume that each word has 4 bytes. Hints:this is a multiword block direct-mapped cache because each cache block (i.e., each cacheline or each cache entry) contains multiple words. The width of the “Byte offset” segmentis 2 (i.e., the lowest two bits of a 32-bit address), which indicates that each word has 4bytes. The width of the “Block offset” segment (i.e., from the 2nd bit to the 5th bit of a 32-bit address) determines the number of words per cache line. A) What is the cache line size (in words)? B) How many entries does the cache have? C) What is the ratio between total bits required for such a cacheimplementation over the data storage bits?
Explain the differences between a directly mapped cache and a fully associative cache.
Explain the difference between a direct-mapped cache and a fully associative cache.
A directly mapped cache is distinguished from an associative cache by its inability to arbitrarily couple data elements.
For a direct-mapped cache design with a 32-bit address, the following bitsof the address are used to access the cache. Use the table below. a. What is the cache block size (in words)?b. How many entries does the cache have?c. What is the ration between total bits required for such a cache implementation overthe data storage bit?
Cache Mapping Technique 1. Suppose a computer usingdirect-mapped cache has 2 bytes of byte=addressable main memory and a cache of32 blocks, where each cache block contains 16 bytes.a) How many blocksof main memory are there?b) What is theformat of a memory address as seen by the cache; that is, what are the sizes ofthe tag, block, and offset fields?c) To which cacheblock will the memory address 0x0DB63 map?2. Suppose a computer using fullyassociative cache has 2 bytes of byte-addressable main memory and a cache of128 blocks, where each cache block contains 64 bytes.a) How many blocksof main memory are there?b) What is theformat of a memory address as seen by the cache; that is, what are the sizes ofthe tag and offset fields?c) To which cacheblock will the memory address 0x01D872 map?3. A 2-way set-associative cacheconsists of four sets. Main memory contains 2K blocks of 8 bytes each and byte addressingis used.a) Show the mainmemory address format that allows us to map addresses from…
Computer Science Compare 4-block caches (Direct mapped (One-way set), 2-way set associative, fully associative), in terms of miss rate when you get block access sequence as following: 1, 2, 3, 2, 4, 4, 4 Note: Show your steps for each cache type.
A cache is organized as a 4 way set associative cache Each set's cache line consists of 4 words (meaning there are 16 bytes per line, for each set of the cache). Each set individually has one Valid bit, and one Dirty bit, for each line. The tag field of this cache is 8 bits wide. The address is 32 bits wide. Question 1c) What is the cache size? (Meaning the number of kilobytes of data being stored in this cache, ignoring the tag, dirty, and valid bits) Question 1d) If this same sized cache (meaning the number of kilobytes of the data part from the question 1c above) are instead organized as a direct mapped cache, what is the total number of 'memory bitcells' needed to design this cache instead (meaning how many bitcells including the tag, dirty, and valid bits? (Assume that the number of cache lines are not changing and that all the bytes of all four sets are now coalesced into one set, thus making it a direct mapped cache)