Database System Concepts
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Plz use c language to correct the errors in the coding, plz don't change the library and just correct the errors
#include<stdio.h> define MAXS 1824 int concat(char*s1, char s2, char s3); int main(void) { int i, j, n; char si[]="agree", s2[]="able"; char s3 [MAXS]; printf("Enter string si: "); scanf("%c", &s1); printf("Enter string s2: "); scanf("%c", 8s2); } n = concat(s1, s2,s3); printf("which is the length of: "); scanf("%d", &n); return e; } int concat(char*s1, char*s2, char*s3){ int i; while (s1[1]!= '\0'){ $3[1]=s1[1]; while (s2[j]!= '\0'){ i++; $3[1]=s2[1]; $3[n]='\0'; while (s3[n]!= '\0'){ ++; } printf("The concatenation of the string: c" "and the string: %c" "is the string Xc"); scanf("%c %e %c", 8s1, 8s2, 8s3); return n;
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Transcribed Image Text:#include<stdio.h> define MAXS 1824 int concat(char*s1, char s2, char s3); int main(void) { int i, j, n; char si[]="agree", s2[]="able"; char s3 [MAXS]; printf("Enter string si: "); scanf("%c", &s1); printf("Enter string s2: "); scanf("%c", 8s2); } n = concat(s1, s2,s3); printf("which is the length of: "); scanf("%d", &n); return e; } int concat(char*s1, char*s2, char*s3){ int i; while (s1[1]!= '\0'){ $3[1]=s1[1]; while (s2[j]!= '\0'){ i++; $3[1]=s2[1]; $3[n]='\0'; while (s3[n]!= '\0'){ ++; } printf("The concatenation of the string: c" "and the string: %c" "is the string Xc"); scanf("%c %e %c", 8s1, 8s2, 8s3); return n;
Write a function called concat () which takes two strings s1 and 62 as arguments and sets up a third string, s3, in which the second string is concatenated (i.e. added) to the end of the first string. In other words, the third string consists of all the characters of s1 up to but not including the null character followed by all the characters in s2 including the final null character. For example, if s1 is "agree" and s2 is "able", then s3 would be "agreeable". The function concat() should also return the length of s3. Include a main program which tests your function. Here is a sample run: The concatenation of the string: and the string: "able" is the string: "agreeable" which is 9 characters in length. agree"
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Transcribed Image Text:Write a function called concat () which takes two strings s1 and 62 as arguments and sets up a third string, s3, in which the second string is concatenated (i.e. added) to the end of the first string. In other words, the third string consists of all the characters of s1 up to but not including the null character followed by all the characters in s2 including the final null character. For example, if s1 is "agree" and s2 is "able", then s3 would be "agreeable". The function concat() should also return the length of s3. Include a main program which tests your function. Here is a sample run: The concatenation of the string: and the string: "able" is the string: "agreeable" which is 9 characters in length. agree"
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