Problem 1IR Spectrum(liquid film)17180.0P2000v (cm')4000300016001200800100-Mass Spectrum 0.5438060UV SpectrumM*721.033.3 mg/10 ml1.0 cm cellsolvent : ethanol20571.540801201602002402802002503002 (nm)350m/e13C NMR Spectrum(50.0 MHz, CDCI, solution)solventproton coupledproton decoupled2001601208040O 8 (ppm)'H NMR Spectrum(200 MHz, CDCI, solution)TMS10987654318 (ppm)90What is the IR andHNMRand CNMR for the C4H80um Foroh% of base peakabsorbance

The structure of C4H8O has been deducedcin the following step.

Problem 1 IR Spectrum (liquid film) 1718 0.0P 1600 2000 V (cm") 4000 3000 1200 800 100- 43 Mass Spectrum 0.5 80 60F M+ UV Spectrum 1.0 40 33.3 mg/10 ml 1.0 cm cell solvent : ethanol CH3O 1.5. 200 240 280 300 250 2 (nm) 40 80 120 160 200 350 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) solvent proton coupled prolon decoupled 200 160 120 80 40 O 8 (ppm) 'H NMR Spectrum (200 MHz, CDCI, solution) TMS 6 4 3 2 1 8 (ppm) 10 8 % of base peak absorbance

Problem 1 IR Spectrum (liquid film) 1718 0.0P 1600 2000 V (cm") 4000 3000 1200 800 100- 43 Mass Spectrum 0.5 80 60F M+ UV Spectrum 1.0 40 33.3 mg/10 ml 1.0 cm cell solvent : ethanol CH3O 1.5. 200 240 280 300 250 2 (nm) 40 80 120 160 200 350 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) solvent proton coupled prolon decoupled 200 160 120 80 40 O 8 (ppm) 'H NMR Spectrum (200 MHz, CDCI, solution) TMS 6 4 3 2 1 8 (ppm) 10 8 % of base peak absorbance

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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