Problem 4: A coal car of mass mj = 3395 kg is rolling down the tracks at a velocity of v; = 4.3 m/s when a loader drops a load of coal m2 = 6196 kg into the car. Randomized Variables m1 = 3395 kg m2 = 6196 kg Vi = 4.3 m/s Part (a) What is the momentum of the system in (kg m)/s before the coal is added? Numeric : Anumeric value is expected and not an expression. P = Part (b) What is the velocity after the coal is added in meters per second? Numeric : Anumeric value is expected and not an expression. Part (c) If you measured the final velocity of the car to be 1 m/s and the initial mass of the car remains the same, how much coal was added to the car in kg? Numeric : A numeric value is expected and not an expression. m2' =

Classical Dynamics of Particles and Systems
5th Edition
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter9: Dynamics Of A System Of Particles
Section: Chapter Questions
Problem 9.35P
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Linear Momentum Q4: Please answer all parts with reasoning and explain step by step in detail (even if minor).
Problem 4: A coal car of mass m1 = 3395 kg is rolling down the tracks at a velocity of v; = 4.3 m/s when a loader drops a load of
coal m2= 6196 kg into the car.
Randomized Variables
m] = 3395 kg
m2 = 6196 kg
Vi = 4.3 m/s
Part (a) What is the momentum of the system in (kg m)/s before the coal is added?
Numeric : A numeric value is expected and not an expression.
P=
Part (b) What is the velocity after the coal is added in meters per second?
Numeric : A numeric value is expected and not an expression.
Part (c) If you measured the final velocity of the car to be 1 m/s and the initial mass of the car remains the same, how much coal was added to the
car in kg?
Numeric : A numeric value is expected and not an expression.
m2' =
Transcribed Image Text:Problem 4: A coal car of mass m1 = 3395 kg is rolling down the tracks at a velocity of v; = 4.3 m/s when a loader drops a load of coal m2= 6196 kg into the car. Randomized Variables m] = 3395 kg m2 = 6196 kg Vi = 4.3 m/s Part (a) What is the momentum of the system in (kg m)/s before the coal is added? Numeric : A numeric value is expected and not an expression. P= Part (b) What is the velocity after the coal is added in meters per second? Numeric : A numeric value is expected and not an expression. Part (c) If you measured the final velocity of the car to be 1 m/s and the initial mass of the car remains the same, how much coal was added to the car in kg? Numeric : A numeric value is expected and not an expression. m2' =
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