2"Problem 5:For the component shown in the figure. Where is the critical location? What steel do you recommendbased on yielding and factor of safety n=3. (F=1000 lb) ==24243,936N PaperBuckling=>(5,00016) (1125/2)J1/64 (1125/9 = 26075,951.25"r = 0.06"F51 Per = ('T ES022FT = 5F lb - in335072518.8786000= 98.99) ²2n, 3

Determine the ratio of Dd. Dd=2''1.25''=1.6 Determine the ratio of rd. rd=0.06''1.25''=0.048

Problem 5: 98.99) For the component shown in the figure. Where is the critical location? What steel do you recommend based on (125/2) 24243,936N P>per Buckling 1/64 (112514 = 26075 2" 4" 1.25" r = 0.06" 2F -.- F 22 T = 5F lb - in S 2

Problem 5: 98.99) For the component shown in the figure. Where is the critical location? What steel do you recommend based on (125/2) 24243,936N P>per Buckling 1/64 (112514 = 26075 2" 4" 1.25" r = 0.06" 2F -.- F 22 T = 5F lb - in S 2

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.9.12P: What is the maximum possible value of the clamping Force C in the jaws of the pliers shown in the...

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Concept explainers

Buckling of columns

The column is described as a vertical member of the structure that carries an axial compressive load, and buckling is a lateral deformation of the column under the application of load.

Question

2"
Problem 5:
For the component shown in the figure. Where is the critical location? What steel do you recommend
based on yielding and factor of safety n=3. (F=1000 lb) ==
24243,936N Paper
Buckling
=>
(5,00016) (1125/2)
J
1/64 (1125/9 = 26075,95
1.25"
r = 0.06"
F
51 Per = ('T ES
02
2F
T = 5F lb - in
3350
72518.87
86000
= 98.99) ²
2n, 3

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