Prove that the moment of inertia of a solid sphere of uniform density, when rotating around a diameter,is 2MR2/5, where M is the mass of the sphere and R is the radius

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Chapter11: Angular Momentum
Section: Chapter Questions
Problem 58P: Shown below is a small particle of mass 20 g that is moving at a speed of 10.0 m/s when it collides...
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Prove that the moment of inertia of a solid sphere of uniform density, when rotating around a diameter,is 2MR2/5, where M is the mass of the sphere and R is the radius.Hint: integrate the infinitesimal volume element in spherical coordinates.

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Step 1

Let us consider a solid sphere of uniform density rotating about the z-axis.

The sphere’s moment of inertia can be represented as,

Physics homework question answer, step 1, image 1

Here, dm and z represent the sphere’s small volume element’s mass, and the volume element’s mass distance from the Z-axis, respectively.

From spherical coordinates,

Physics homework question answer, step 1, image 2

Here, r and θ represent the volume element’s distance from the origin and the angle that r makes with the z-axis, respectively.

Also,

Physics homework question answer, step 1, image 3

Here, ρ and dV represent the sphere’s mass density, and the volume element’s volume, respectively.

Thus,

Physics homework question answer, step 1, image 4

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