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- java getDup accepts an array and returns an int. If there is any element is duplicated, the method counts how many of those present in the array. Example : getDup(["1","2","aa"',"1"]) returns:2 ("1" is duplicated and there are two "1"s so return is 2) class Main { public static int getDup(String[] r) { } public static void main(String[] args) { Scanner in = new Scanner(System.in); String [] strs = new String[in.nextInt()]; for(int i=0; i < strs.length; i++) { strs[i] = in.next(); } System.out.println(getDup(strs)); } } hint: you will need a nested array the will run on the array we get from the method argument. inside the nested loop you will need to check if the main array element is equal to the currentWrite Java statements to add the integers 1001, 1100, and 1110 to the resulting ArrayList import java.util.*;public class test { public static void main(String[] args) { //Set n =25 int n = 25; //ArrayList of Integer type with size,n=25 ArrayList<Integer> list = new ArrayList<Integer>(n); for(int i = 0;i<n;i++){ //Assign -1 to all the objects of the array list,list list.add(-1); } //Add 1001 to the list list.add(1001); //Add 1100 to the list list.add(1100); //Add 1110 to the list list.add(1110); //Reset the number of elements in the list becomes 28 //Use size() method to get the size of the list. n=list.size(); //for loop to print the list for(int i = 0;i<n;i++){ System.out.print(list.get(i) + " "); } }} 1. Write the Java statement to display the size of the resulting ArrayList from above.Given an array of numbers, and an integer, find the last index that that integer appears in the array. If the number is not found, return -1. import java.util.ArrayList;public class LastIndexFound{public static int solution(ArrayList<Integer> nums, int numToFind){// ↓↓↓↓ your code goes here ↓↓↓↓return 0;}}
- import java.util.ArrayList;import java.util.Random; class Main { public static void main(String[] args) { Random rand = new Random(); ArrayList<Integer> a = new ArrayList<Integer>(); for(int i = 0; i < 100; i++) { a.add(rand.nextInt(100)); } print(a); System.out.println("----"); sort(a); print(a); // simplified Quicksort public static void sort(ArrayList<Integer> a) { if (a.size() <= 1) return; // Pick a Pivot int m = a.size() / 2; int pivot = a.get(m); } ArrayList<Integer> smaller = new Arraylist<Integer>(); ArrayList<Integer> same = new ArrayList<Integer>(); ArrayList<Integer> larger = new ArrayList<Integer>(); for (Integer x : a) { if (x < pivot) { smaller.add(x); } else if(x > pivot) { larger.add(x); } else { same.add(x); } } sort(smaller); sort(larger); a.clear(); a.addAll(smaller);…in java wirte a method that given an integer array, computes and returns an integer x. the starting value of x is equal to the array length. for every odd element in the array, substract it from x, and for every even element in the array add it to x . Example: Array: [13,2,3,4,5] Result: x=5-13+2-3+4-5 x= -10Create Test Suit for all test cases public class Arraymethod { public static void main(String[] args) { int [] array = {2,5,10,8,9,3}; System.out.println("Sum of array elements is:"+sum(array)); System.out.println("Average of array elements is:"+avg(array)); System.out.println("Maximum element of array is:"+max(array)); System.out.println("Minimum element of array is:"+min(array)); } //method for calculating sum of array elements public static int sum(int[] array) { int sum = 0; for(int i=0; i array[i]) { min = array[i]; } } return min; } } Create Test Suit for all test cases
- import java.util.Arrays; import java.util.Random; public class Main { public void Start(){ int[] array = {3, 6, 1, 4, 2, 9, 7, 8, 5, 0}; int key = 1; Arrays.sort(array); //sort array int result = binarySearch(array,key); //Print values in array after sort System.out.println(result); } int binarySearch(int arr[], int key){ // put your code here. } public static void main(String[] args) { Main main = new Main(); main.Start(); } } --------------------------------------------------------------------------------------------------------------------------------------------------------- Given a sorted array named arr of n elements, write a function to search for a given element x in arr. If the element is present, return the index of x in the array. If the element is not present, return -1. Don't forget that arrays are 0-base-indexed, meaning that the first element in…Starter code for PhotoLineups.java import java.util.Scanner;import java.util.ArrayList; public class PhotoLineups { // TODO: Write method to create and output all permutations of the list of names. public static void printAllPermutations(ArrayList<String> permList, ArrayList<String> nameList) { } public static void main(String[] args) { Scanner scnr = new Scanner(System.in); ArrayList<String> nameList = new ArrayList<String>(); ArrayList<String> permList = new ArrayList<String>(); String name; // TODO: Read a list of names into nameList; stop when -1 is read. Then call recursive method. }}Complete this code in Java import java.util.Scanner; import java.util.ArrayList; public class SET { ArrayListlist; int length; public SET(); { list=new ArrayList<>(10); length=0; } public SET(int cap) { list=new arrayList<>(cap); length=0; } public int getLength() { return length; } } public class SetApplication { public static void main(String[] args) { SET st=new SET(); System.out.println(st.getLength()); } }
- Java: Use array class. Thanks!JAVA Using methods and arrays, write a program that Creates and fills an array A of size 100 filled with random integers in the range 1 to 100 inclusive. • prints it out in 5 lines (20 values per line). • Calculates the sum of the even elements of A and print it out.// MergeSortTest.java// Sorting an array with merge sort.import java.security.SecureRandom;import java.util.Arrays; public class MergeSortTest { // calls recursive sortArray method to begin merge sorting public static void mergeSort(int[] data) { sortArray(data, 0, data.length - 1); // sort entire array } // splits array, sorts subarrays and merges subarrays into sorted array private static void sortArray(int[] data, int low, int high) { // test base case; size of array equals 1 if ((high - low) >= 1) { // if not base case int middle1 = (low + high) / 2; // calculate middle of array int middle2 = middle1 + 1; // calculate next element over // split array in half; sort each half (recursive calls) sortArray(data, low, middle1); // first half of array sortArray(data, middle2, high); // second half of array // merge two sorted arrays after split calls…