public class StackTest{ public static void main(String[] args){ Stack s = new Stack(); for(int i = 0; i< 10; i++) s.push(i); s.pop(); s.pop(); s.pop(); System.out.println(s.peek()); } } what is the output?

Question 1 Analyze the following code: import java.util.*: public class Test { public static void main (String[] args){ PriorityQueue queue = new PriorityQueue( Arrays.asList (60, 10, 50, 30, 40, 20)): while (!queue.isEmpty()) System.out.print(queue.poll () + " "); O The program displays 10 20 30 40 50 60 O The program displays 60 50 40 30 20 10 The program displays 60 10 50 30 40 20 O There is no guarantee that the program displays 10 20 30 40 50 60 A Moving to the next question prevents changes to this answer

OCaml Code: The goal of this project is to understand and build an interpreter for a small, OCaml-like, stackbased bytecode language. Make sure that the code compiles correctly and provide the code with the screenshot of the output. Make sure to have the following methods below:    -Push integers, strings, and names on the stack -Push booleans -Pushing an error literal or unit literal will push :error: or :unit:onto the stack, respectively -Command pop removes the top value from the stack -The command add refers to integer addition. Since this is a binary operator, it consumes the toptwo values in the stack, calculates the sum and pushes the result back to the stack - Command sub refers to integer subtraction -Command mul refers to integer multiplication -Command div refers to integer division -Command rem refers to the remainder of integer division -Command neg is to calculate the negation of an integer -Command swap interchanges the top two elements in the stack, meaning that the…

0:00 I ZVV 58 Stack s - new Stack(); s. push(10); s. push(20); s. push(30); s. push(40); // stack created with elements- 10 20 30 40 59 60 61 62 63 64 65 sum(s); 66 public static void sum(stack s){ Integer sum = 0; stack tmp = new Stack(); // move the stack to new stack, it will be in reverse orde // simultaneously sum the elements while (Is.isEmpty())( tmp.push(s.pop(); sum t tmp.peek(); 67 68 69 70 71 72 73 74 sum t= tmp.peek (); 74 75 // move to original stack while (Itmp.isEmpty()){ s.push(tmp.pop()); system.out.println("sum= "+sum.tostring()); OUTPUT- 10 pushed into stack 20 pushed into stack 30 pushed into stack 40 pushed into stack 40 pushed into stack 30 pushed into stack 20 pushed into stack 10 pushed into stack 10 pushed into stack 20 pushed into stack 30 pushed into stack 40 pushed into stack Sum= 100 Sum of 10, 2O, 30, 40 = 100 I hope it helps. For any doubt, feel free to ask in comments, and give upvote if u get the answer.

This is java. Write the java code that takes the contents of a stack and places it in a queue and takes the contents of a queue and puts it in a stack. Your code can only use stack and queue data structure. swapStackAndQueue(stack, queue) //method call This is java.

import java.util.*;import java.io.*; public class HuffmanCode {     private Queue<HuffmanNode> queue;        private HuffmanNode overallRoot;                 public HuffmanCode(int[] frequencies) {                queue = new PriorityQueue<HuffmanNode>();                                for (int i = 0; i < frequencies.length; i++) {                        if (frequencies[i] > 0) {                                HuffmanNode node = new HuffmanNode(frequencies[i]);                                node.ascii = i;                                queue.add(node);                        }                }                overallRoot = buildTree();              }                 public HuffmanCode(Scanner input) {                overallRoot = new HuffmanNode(-1);                while (input.hasNext()) {                        int asciiValue = Integer.parseInt(input.nextLine());                        String code = input.nextLine();                        overallRoot =…