Python code using pandas to find the users with the highest aggregate scores (over all their posts) for the whole dataset. You should restrict your results to only those whose aggregated score is above 10,000 points, in descending order. Code should generate a dictionary of the form {author:aggregated_scores ... }.

Create a static dictionary with a number of users and with the following values:  First name Last name Email address Password Ask the user for:          5. Email address        6. Password Loop (for()) through the dictionary and if (if()) the user is found print the following:          7. Hello, first name last name you have successfully logged in        8. Notify the user if the password and email address are wrong        9. Additional challenge: if you want the program to keep asking for a username and password when the combination is wrong, you will need a while() loop.      10. Save the file as assignment03yourlastname.py

def get_nearest_station(my_latitude: float, my_longitude: float, stations: List['Station']) -> int: "''Return the id of the station from stations that is nearest to the location given by my_latidute and my_longitude. In the case of a tie, return the ID of the last station in stations with that distance. Preconditions: len(stations) > 1 » get_nearest_station(43.671134, -79.325164, SAMPLE_STATIONS) 7571 » get_nearest_station(43.674312, -79.299221, SAMPLE_STATIONS) 7486

Program - Python Problem below the code This is my code for a dictionary of student's test scores. def main():#Create a dictionary with name as key#Marks as the list of valuesstudent_dictionary=\{'Brian': [94, 89, 92],'Rachel': [100,90,65],'Jon': [67.5,95,100],'Brit': [0,78,80] ,'Gret': [65,100,78],'Andrea': [55.5,67,79]}#Loop that print name and list of marksfor key, values in student_dictionary.items():print('Name: ', key, " , Marks:", values)#Call main functionif __name__ == '__main__':main()   Problem:  print the dictionary data using a loop that starts with       for key in

This code is a part of a C dictionary. Please write the code for the below requirements.   dict_get   Next, you will implement: char* dict_get (const dict_t* dict, const char* key); This function goes through the list given by dict. If you use the above structure, this means starting at el = dict->head and checking each time whether the key at el is key; if it is not, we set el = el->next, until either key is found, or we reach el == NULL. To compare key with el->key, we need to compare one by one each character in key with those in el->key. Remember that strings in C are just pointers (memory addresses) to the first character in the string, so comparing el->key == key will not do what you want. So how do you even get the length of a string s? You would start at memory location s and advance as long as the byte at s (i.e. *s) is not the end-of-string marker (\0, the NULL character). This can get a bit messy, so luckily, you are allowed to use the string comparison…

FIX THIS CODE Using python Application CODE: import csv playersList = [] with open('Players.csv') as f: rows = csv.DictReader(f) for r in rows: playersList.append(r) teamsList = [] with open('Teams.csv') as f: rows = csv.DictReader(f) for r in rows: teamsList.append(r) plays=len(playersList) for i in range(plays): if playersList[i]['team']=='Argentina' and int(playerlist[i]['minutes played'])<200 and int(playersList[i] ['shots'])>20: print(playersList[i]['last name']) c0=0 c1=0 c2=0 for i in range(len(teamsList)): if int(teamsList[i]['redCards'])==0: c0=c0+1 if int(teamsList[i]['redCards'])==1: c1=c1+1 if int(teamsList[i]['redCards'])==2: c2=c2+1 print("Number of teams with zero redcards:",c0) print("Number of teams with zero redcards:",c1) print("Number of teams with zero redcards:",c2) ratio=0 for i in range(len(teamsList)): if int(teamsList[i]['games']>3) and if int(teamsList[i]['goalsFor'])/int(teamsList[i]['goalsAgainst'])<ratio:…

Which of the below is NOT a responsibility/task for both human and electric computers? Write software Record results Perform calculations Track intermediary steps

This section has been set as optional by your instructor. OBJECTIVE: Write a program in Python that prints the middle value of a dictionary's values, using test_dict from the test_data.py module. NOTE: test_dict is created & imported from the module test_data.py into main.py Example 1: test dict = {'a':1,'b':9,'c':2,'d':5} prints 5 Example 2: test_dict = {'b':9,'d':5} prints 5 Hint: You may(or may not) find the following function useful: list.sort() which sorts the elements in a list. Note: the result is automatically stored in the original list, and return value from the function is None Туре list = [1, 2,3,2,1] After calling: list = [1,1,2,2,3] list.sort(), 339336.2266020 x3zgy7 LAB 13.11.1: Middlest Value (Structured Types) АCTIVITY 0/11 File is marked as read only Current file: test_data.py 1 #This module creates the test_dict to be used in main.py 2 #Reads input values from the user & places them into test_dict 3 dict_size = int(input()) #Stores the desired size of test_dict. 4…

Need help answering this python question Create a dictionary of your friends that you found in 2017 and 2018. So, the keys are '2017' and '2018. For example: friend_solar = {2022: ["James", "Linda"] , 2023: ["Joshua", "Zoey"]} Print the friend's name Ask the user to enter a name of their friends. Then show the friend you found in 2022 or 2023. Ask the user to add a new friend name to the 2022 or 2023 lists (You need also to ask the user what year they want to add the friend name). Then add the entered friend name to the dictionary(2022 or 2023  value)   Print the friends' dictionary on the screen.

Assume the variable definitions references a dictionary.  Write an if statement that determines whether the key 'marsupial' exists in the dictionary.  If so, delete 'marsupial' and its associated value.   If the key is not in the dictionary, display a message indicating so.