Q: In a certain species of plants, violet flower color (V) is dominant over white flower color (v). If p = 0.4 and q = 0.6 in a population of 500 plants, I want you to explain why red is wrong and highlighted is right.

Biology (MindTap Course List)
11th Edition
ISBN:9781337392938
Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Chapter19: Evolutionary Change In Populations
Section: Chapter Questions
Problem 3TYU: The MN blood group is of interest to population geneticists because (a) people with genotype MN...
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Q: In a certain species of plants, violet flower color (V) is dominant over white flower color (v). If p = 0.4 and q = 0.6 in a population of 500 plants,

I want you to explain why red is wrong and highlighted is right. 

ii. heterozygous (Vv):
To calculate the number of individuals expected to be heterozygous (V), you would use
the equation: 2pqX N, where p is the frequency of the dominate allele (in this case, 0.4),
q Is the frequency of the recessive allele (in this case, u.b), and N is the total population
size (in this case, 500). So: 2 x 0.4 X 0.6 x 500 =12(individual expected to be
heterozygous (VV)
The number of heterozygous (Vv) plants in a population of 500 with p=0.4 and q = 0.6 can be calculated
using the formula 2pq X 500. P and q are the frequencies of the dominate and recessive alleles in the
population. In this case, =2 X 0.4 X 0.6 = 0.48. so, the number of heterozygous plants would be,
= 0.48 X 500 = 240.
Transcribed Image Text:ii. heterozygous (Vv): To calculate the number of individuals expected to be heterozygous (V), you would use the equation: 2pqX N, where p is the frequency of the dominate allele (in this case, 0.4), q Is the frequency of the recessive allele (in this case, u.b), and N is the total population size (in this case, 500). So: 2 x 0.4 X 0.6 x 500 =12(individual expected to be heterozygous (VV) The number of heterozygous (Vv) plants in a population of 500 with p=0.4 and q = 0.6 can be calculated using the formula 2pq X 500. P and q are the frequencies of the dominate and recessive alleles in the population. In this case, =2 X 0.4 X 0.6 = 0.48. so, the number of heterozygous plants would be, = 0.48 X 500 = 240.
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