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Asked May 6, 2019
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Q1 & Q2

Q01: Give the structures of both 1,2 and 1,4 adducts resulting from reaction of 1 equivalent of HBr wit
1 Give the structures of both 1,2 and 1,4 adducts resultin
the following compound:
Q # 2 Prepare 3-cyclohexenyl methyl ketone from 1,3-butadiene ?
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Q01: Give the structures of both 1,2 and 1,4 adducts resulting from reaction of 1 equivalent of HBr wit 1 Give the structures of both 1,2 and 1,4 adducts resultin the following compound: Q # 2 Prepare 3-cyclohexenyl methyl ketone from 1,3-butadiene ?

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Expert Answer

Step 1

The given structure is the molecular model of 2, 3-dimethylcyclohexa-1, 3-diene. The given compound, that is, 2, 3-dimethylcyclohexa-1, 3-diene is a conjugated diene. Thus, the addition of HBr to 2, 3-dimethylcyclohexa-1, 3-diene gives two products.

Step 2

The alkene acts as a nucleophile and abstracts a proton from hydrogen bromide, which leads to the formation a secondary carbocation. Bromine attacks the carbocation site and forms a C-Br bond. This leads to the formation of a 1, 2 addition product. The reaction is shown as follows:

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Step 3

The secondary carbocation formed in the previous step is in conjugation with the double bond, so it undergoes resonance and gives another carbocation intermediate...

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