Q1: A 120-V, 1/3-hp 60-Hz, four-pole, split-phase induction motor has the followingimpedances:R1-1.80ΩΧ1-2.40 Ω ΧΜ= 60 ΩR22.50ΩΧ2 = 2.40 ΩAt a slip of 0.05, the motor's rotational losses are 51 W.The rotational losses may be assumed constant over the normal operating range ofthe motor. If the slip is 0.05, find the following quantities for this motor:(a) Input power(b) Air-gap power(c) Pcony(d) Pout(e) t ind) T load(g) Overall motor efficiency(h) Stator power factor

As per the guidelines, we supposed to answer the first three-part of the question at a time so…

Q1: A 120-V, 1/3-hp 60-Hz, four-pole, split-phase induction motor has the following impedances: R1 -1.80 ΩΧΙ-2.40 Ω ΧΜ= 60 Ω R2-2.50 ΩΧ2 = 2.40 Ω At a slip of 0.05, the motor's rotational losses are 51 W.

Q1: A 120-V, 1/3-hp 60-Hz, four-pole, split-phase induction motor has the following impedances: R1 -1.80 ΩΧΙ-2.40 Ω ΧΜ= 60 Ω R2-2.50 ΩΧ2 = 2.40 Ω At a slip of 0.05, the motor's rotational losses are 51 W.

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)

10th Edition

ISBN:9781337399128

Author:Russell E. Smith

Publisher:Russell E. Smith

Chapter8: Basic Electric Motors

Section: Chapter Questions

Problem 28RQ: What are the advantages and disadvantages of using the following types of motors? shaded-pole...

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Concept explainers

Single Phase Induction Motor

The single-phase induction motor or engine consists of a single rotating phase in the stator and a rotating cage in the rotor. When phase one supply is connected to the stator winding, a magnetic field is generated. In the pulsating field, the rotor does not rotate due to inertia. So, a single-phase import motor does not start and requires some initial methods.

Question

Q1: A 120-V, 1/3-hp 60-Hz, four-pole, split-phase induction motor has the following
impedances:
R1-1.80ΩΧ1-2.40 Ω ΧΜ= 60 Ω
R22.50ΩΧ2 = 2.40 Ω
At a slip of 0.05, the motor's rotational losses are 51 W.
The rotational losses may be assumed constant over the normal operating range of
the motor. If the slip is 0.05, find the following quantities for this motor:
(a) Input power
(b) Air-gap power
(c) Pcony
(d) Pout
(e) t ind
) T load
(g) Overall motor efficiency
(h) Stator power factor

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