Q1- Write a program in assembly language for the 8085 microprocessor to receive 10 bytes of data via the SID and store it at the memory address (3000H to 3009H) using a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When you receive each byte of the required bytes, you must adhere to the following: The bits of two high bits will be received at the beginning of the reception (start bits), after that the data bits will be received, after that the low bit of the stop bit will be received (stop bit). The following flowchart will help you, but you should notice that this flowchart deals with one byte, and you are required to deal with 10 bytes The solution must be integrated and include the calculation of the baudrate delay time Ol@[[[[[C+40) No Yes SIDATA Read SID It is Start Bit? Yes Wait for Half-Bit Time Set up Bit Counter Wait Bit Time Read SID Save Bit Decrement Bit Counter Are All Bits Received? No Add Bit to Previous Bits Go Back to Get Next Bit Return

Translate the following C code to MIPS assembly, assuming that the variables f, g, h, i, and j correspond to registers $50, $s1, $s2, $s3, and $54 respectively. Also, assume that the base addresses of arrays A and B are contained in $56 and $s7 respectively, and that each element of arrays A and B are 4-byte words: B[8] =A[i] + A[j]; Which of the following MIPS assembly code snippets correctly performs the above operation? sll $t1, $s3, 2; add $t1, $56, $t1; lw $12, 0($t1); sll $t1, $s4, 2; add $11, $s6, St1; lw $13, 0($t1); add $12, $12, $t3; sw $12, 32($s7) sll $t1, $s3, 2; add $11, $s6, $t1; lw $12, 0($t1); sll $t1, $s4, 2; add $11, $s6, $t1; lw $13, 0($t1); add $t4, $12, $t3; sll $15, $t0, 2; add $15, $s7, $15; sw $t4, 32($15) Iw $11,0($s3); Iw $12, 0($s4); add $13, $11, $12; sw $13, 32($s7) sll $t1, $s3, 2; lw $12, 0($t1); sll $t1, $s4, 2; lw $13, 0($t1); add $t4, $t2, $t3; sw $t4, 32($s7)

sim8085

Use the following data declarations. Assume that the offset of byte Val is 00000000: .data byte Val sbyte 1,2,3.-7h word Val word 1000h.2000h 3000h, 4000h dwordVal dword 34567890h, 90785634h, 1234674Sh Show the value of the final destination operand after each of the following code fragments has executed: (If any instructions is invalid, indicate "INV" as the answer and briefly explain why) a. moy di 2 mov al, byte Val[di] b. mov bx, word Val mov esi, offset wordVal+4 xchg bx, [esi] R c. movsx cx, byte Val+3 d. mov ax, word ptr [dwordVal mov bl. byte ptr [dwordVal +10] e. mov al, 80h number add al 40h signed ;signed number answer al-= answer bx= answer (show your answer in binary) CX- answer |esi= answer bl= SF=