QUESTION 2 To test the effect of a new medication on pulse rate, the researcher randomly selected the 60 subjects into two groups of 30. New medicine and placebo were given to Group 1 and Group 2, respectively. Below is the Minitab output. Two-Sample T-Test and CI St Dev Group 1 Mean SE Mean 30 65.20 30 70.30 7.80 1.4 2 8.40 1.5 Difference = mu (1) - mu (2) Estimate for difference: 95% CI for difference: -5.10 (-9.29, -0.91) T-Test of difference = 0 (vs not =) : T-Value == -2.44 P-Value=0.018 DF=57 i) State the formula you would use to construct a 95% confidence interval. Include the value of a and degrees of freedom that you will use to find the critical value in the formula

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
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ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
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QUESTION 2
To test the effect of a new medication on pulse rate, the researcher randomly selected the 60
subjects into two groups of 30. New medicine and placebo were given to Group 1 and Group
2, respectively. Below is the Minitab output.
Two-Sample T-Test and CI
Group
1
N
Мean
StDev
7.80
SE Mean
30
65.20
1.4
2
30
70.30
8.40
1.5
Difference = mu (1) - mu (2)
Estimate for difference: -5.10
95% CI for difference:
(-9.29, -0. 91)
T-Test of difference = 0 (vs not =): T-Value = -2.44
P-Value=0.018
DF=57
i) State the formula you would use to construct a 95% confidence interval. Include the value
of a and degrees of freedom that you will use to find the critical value in the formula
Transcribed Image Text:QUESTION 2 To test the effect of a new medication on pulse rate, the researcher randomly selected the 60 subjects into two groups of 30. New medicine and placebo were given to Group 1 and Group 2, respectively. Below is the Minitab output. Two-Sample T-Test and CI Group 1 N Мean StDev 7.80 SE Mean 30 65.20 1.4 2 30 70.30 8.40 1.5 Difference = mu (1) - mu (2) Estimate for difference: -5.10 95% CI for difference: (-9.29, -0. 91) T-Test of difference = 0 (vs not =): T-Value = -2.44 P-Value=0.018 DF=57 i) State the formula you would use to construct a 95% confidence interval. Include the value of a and degrees of freedom that you will use to find the critical value in the formula
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