Question provided in attachment kindly see and my problem to the solution provided below kindly see . i need output with 2 decimal places only. so correct my code according to that. ------------my solution----------------- #!/bin/bash squareroot(){ sr=$(echo "$1" | awk '{print sqrt($1)}') echo "The square root of $1 is $sr" } echo "Enter a number" read n squareroot $n
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Question provided in attachment kindly see and my problem to the solution provided below kindly see .
i need output with 2 decimal places only. so correct my code according to that.
------------my solution-----------------
#!/bin/bash
squareroot(){
sr=$(echo "$1" | awk '{print sqrt($1)}')
echo "The square root of $1 is $sr"
}
echo "Enter a number"
read n
squareroot $n
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