Reaction of 1-butene (above) with HBr might, in principle, lead to a mixture of two alkyl bromide addition products. Draw these two alkyl bromides.
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Reaction of 1-butene (above) with HBr might, in principle, lead to a mixture of two alkyl bromide addition products. Draw these two alkyl bromides.
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- Which reaction would you expect to be faster, addition of HBr to cyclohexene or to 1-methylcyclohexane? Explain.What are ALL of the products of buta-1,3-diene and bromine water? I know how to get to the major product (bromine and OH both to the left of the double bond) but don't know how to get to the minor product (bromine to the left, OH to the right)?Identify possible 1,4-products of this reaction:
- draw the two possible carbocations that can form when this alkene reacts with a strong acid (such as HBr or H3O+). of the two structures you drew, circle the more stable carbocationWhat are the possible alkene products in the reaction below? Draw them and select which one is expected to predominate1, part A) In the reaction below, draw all of the possible products. 1, part B) For all the products you have drawn, draw their corresponding carbocations while also identifying if each is 1o/2o/3o carbocation. In addition, starting from alkene - provide complete accurate arrow-pushing mechanisms of each carbocation formation. 1, part C) In part B, circle the carbocation which is *most* stable, indicate why.
- 10. Use Hammond's postulate to determine which alkene in each pair would be expected to form a carbocation faster in an electrophilic addition reaction. Choose which is the more reactive compound (in the box) for both pairs.Draw the mechanism of the hydroboration reaction for 1-octene. Why are carbocation rearrangements not observed in this reaction?The 1,2‑dibromide is synthesized from an alkene starting material. Draw the alkene starting material. Clearly, show stereochemistry of the alkene.
- 1-bromo-1-methylcyclopentane is being reacted with sodium ethoxide in diethyl ether Ethoxide will remove a proton from one of the carbons alpha to the carbon bonded to bromine. The electron pair from the carbon-hydrogen bond will move toward the 1 carbon to form a new pi bond. This will push off the bromine, which will leave with its electron pair to form a bromide leaving group. This will form the product 1-methylcyclopentene and sodium bromide as byproduct. So, is this reaction following an E1 or E2 mechanism? Write out the rate law for this reaction. Draw a reaction coordinate diagram for this reaction.The 3D image below is that of an allylic carbocation intermediate formed by the protonation of a conjugated diene with HBr. Draw structural formulas for the final reaction products.1,3-pentadiene reacts with HBr. When the double bond at the 3-position reacts, the hydrogen attaches to the 4-carbon, thus forming an allylic carbocation with delocalized electrons. This carbocation has another resonance structure. Because there are equal amounts of diene and hydrogen bromide, in which molecule only one of the double bonds reacts. Which of the following correctly describes this new resonance structure? a) It has a double bond between carbons 3 and 4 b) It has a positive charge on carbon 2 c) It has a positive charge on carbon 4 d) It has a double bond between carbons 2 and 3
