Recall that the transverse velocity for Poiseuille flow is Ap u(r) = 4µL + cị Inr+ c2, 0 < r < R, where Ap/L is the (constant) pressure gradient, u is the dynamic viscosity, and L is the length of the tube. Since the solution can't blow up at r = 0, c¡ = 0, and c, is determined by the no-slip condition u(R) = 0. Integrating the resulting solution over the cross- section of the tube gives the flux TR* Ap Qo 8µ L Now imagine that the tube has a central catheter so that R

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Recall that the transverse velocity for Poiseuille flow is
Др
4µL
u(r) =
P² + c1
Inr + c2,
0 < r < R,
where Ap/L is the (constant) pressure gradient, u is the dynamic viscosity, and Lis the length of the tube. Since the solution can't
blow up at r = 0, c1 = 0, and c2 is determined by the no-slip condition u(R) = 0. Integrating the resulting solution over the cross-
section of the tube gives the flux
TRA Ap
Qo
8µ L
1
R< r < R. Use the solution for u above and apply no-slip conditions at
3
Now imagine that the tube has a central catheter so that
1
R and r = R to compute the flux Q for the catheterized tube.
3
r =
Transcribed Image Text:Recall that the transverse velocity for Poiseuille flow is Др 4µL u(r) = P² + c1 Inr + c2, 0 < r < R, where Ap/L is the (constant) pressure gradient, u is the dynamic viscosity, and Lis the length of the tube. Since the solution can't blow up at r = 0, c1 = 0, and c2 is determined by the no-slip condition u(R) = 0. Integrating the resulting solution over the cross- section of the tube gives the flux TRA Ap Qo 8µ L 1 R< r < R. Use the solution for u above and apply no-slip conditions at 3 Now imagine that the tube has a central catheter so that 1 R and r = R to compute the flux Q for the catheterized tube. 3 r =
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