Question
Asked Oct 20, 2019
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I have calculated this problem wrong twice, and I could use some guidance. 

 

Thanks much. 

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Exactly 14.4 mL of water at 33.0 °C is added to a hot iron skillet. All of the water is converted into steam at
100.0°C. The mass of the pan is 1.45 kg and the molar heat capacity of iron is 25.19 J/(molC). What is the
temperature change of the skillet?
°C
54.32
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See Periodic Table Feedback See Hint Exactly 14.4 mL of water at 33.0 °C is added to a hot iron skillet. All of the water is converted into steam at 100.0°C. The mass of the pan is 1.45 kg and the molar heat capacity of iron is 25.19 J/(molC). What is the temperature change of the skillet? °C 54.32

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Expert Answer

Step 1
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wateu= Noluue 14.4 (mass of - 14. 4ML Tnitial Tempeaue = 330'c final Temperatune looc Mass pan 2514 /lc Molav heat capacity of iron

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Step 2
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Heat (q Mc(Te-T (loo-19'c x 4184 4518-72 J

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Step 3
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Heat necded to vaporize tue watu is caleulsled fplons: natu watu x 14. 4 2260 J 32544 J

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Physical Chemistry

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