Suppose that binary heaps are represented using explicit links. Give a simple algorithm to find the tree node that is at implicit position i. instructions: provide Java-like pseudocode. The implicit position of a node refers to the index it would have if the heap was stored in the array format reviewed in class (first element at index 1).

Please be thorough with explanation   (a) Consider implementing a stack as a class that relies on a singly linked list, maintaining pointers to both the start and end of the singly linked list in the main object. You consider two possibilities. The first is to push (insert) to the beginning and pop (remove) from the beginning of the linked list. The second is to push to the end and pop from the end of the linked list. Is one of these possibilities better than the other? Briefly explain your answer.

A(n) array can be used in an array implementation of a queue to avoid an overflow error at the rear of the queue when the queue is not full.

Create a computer programme to arrange objects in a stack so that the smallest ones are on top. Although you are allowed to utilise an extra temporary stack, you are not allowed to transfer the components into another data structure (such an array). The following operations are supported by the stack: push, pop, peek, and is Empty.

Push 13 to the following min-heap and write the resulting heap array in the answer space. Write the array like a normal C++ array (e.g.: {67, 54, 123, ...}). 54 51 62 27 59 12pt ✓ Paragraph 28 ⠀ 50 Edit View Insert Format Tools Table 3 44 22 24

char ** doubleIt (char **arr, int *maxsize); The doubleIt function will increase the heap size by doubling the original space. The functions takes 2 arguments: 1. A double pointer of type char called arr. This is a 2D dynamic array that contains words (strings) from the respective category (noun, verb, adjective, preposition). This is the original heap. 2. A pointer of type int called maxsize. This pointer holds the address of an integer that keeps track of the maximum amount of strings the 2D dynamic array can store. When this function is invoked, the current size of the dynamic array is at capacity so the values should match. This value will need to be multiplied by 2. The function allocates a new heap that is twice the size of the original heap and copy the values from the original heap into the new heap. One important note about this is that you have to properly copy the values over in order to avoid segmentation fault. Think about how this can be avoided. That is part of the…

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