Suppose you are testing Ho =.45 versus Ha > .45 random sample of 310 people produces a value of p= .465. Use= .05 to test this hypothesis. %3D Instruot
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- Suppose we are interested in the relationship between individuals’ place of residence (rural versus urban) and their political affiliation (Republican versus Democrat). A random sample of 100 individuals yields the following crosstabulation: Political Affiliation Place of Residence Republican Democrat Rural 21 29 Urban 14 36 a) In words, what is the null hypothesis to be tested? b) Is the relationship between place of residence and political affiliation statistically significant at the .05 level? (Be sure to show the statistics that lead to your decision.) c) Compute and interpret an appropriate measure of association for the relationship between these two variables.Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.A manager for an insurance company believes that customers have the following preferences for life insurance products: 20% prefer Whole Life, 10% prefer Universal Life, and 70% prefer Life Annuities. The results of a survey of 200 customers were tabulated. Is it possible to refute the sales manager's claimed proportions of customers who prefer each product using the data? Product Number Whole 78 Universal 34 Annuities 88 Step 1 of 10 : State the null and alternative hypothesis. Step 2 of 10: What does the null hypothesis indicate about the proportions of customers who prefer each insurance product? Step 3 of 10: State the null and alternative hypothesis in terms of ehe expected proportions for each category. Step 4 of 10: Find the expected value for the number of customers who prefer whole life. Round your answer to two decimal places. Step 5 of 10: Find the expected value for the number of customers who prefer universal life. Round your answer to two…