tert-Butyl alcohol is a solvent with a Kf of 9.10 °C/m and a freezing point of 25.5°C. When 0.807 g of an upknown colorless nonelectrolyte liquid was dissolved in 11.6 g of tert-butyl alcohol, the solution froze at 15.3 °C.Which of the following is most likely the identity of this unknown liquid? > View Available Hint(s) O ethylene glycol (molar mass = 62.07 g/mol) O 1-octanol (molar mass = 130.22 g/mol) O glycerol (molar mass = 92.09 g/mol) %3D O 2-pentanone (molar mass = 86.13 g/mol) O 1-butanol (molar mass = 74.12 g/mol) Submit

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter13: Solutions And Their Behavior
Section: Chapter Questions
Problem 104SCQ: Sodium chloride (NaCl) is commonly used to melt ice on roads during the winter. Calcium chloride...
icon
Related questions
Question
I Review | Constants | Periodic Table
The molar mass of a compound expresses the ratio
of mass to moles:
mass in grams
Part A
molar mass =
number of moles
tert-Butyl alcohol is a solvent with a K¡ of 9.10 °C/m and a freezing point of 25.5 °C. When 0.807 g of an upknown colorless
nonelectrolyte liquid was dissolved in 11.6 g of tert-butyl alcohol, the solution froze at 15.3 C.Which of the following is most
likely the identity of this unknown liquid?
This quantity can be determined experimentally by
accurately measuring the mass of the sample and
determining the corresponding number of moles
based on some property of the sample. Freezing-
point depression and osmotic pressure
measurements are frequently used to calculate the
number of moles in solution for this type of
determination.
> View Available Hint(s)
O ethylene glycol (molar mass = 62.07 g/mol)
%3D
Freezing-point depression is equal to
O 1-octanol (molar mass = 130.22 g/mol)
%3D
AT = Kt m
O glycerol (molar mass = 92.09 g/mol)
where AT is the change in temperature, KĘ is the
molal freezing-point-depression constant, and m is
the molality in moles of solute per mass of solvent.
O 2-pentanone (molar mass = 86.13 g/mol)
%3D
O 1-butanol (molar mass =
74.12 g/mol)
Osmotic pressure is equal to
II = MRT
Submit
where II is the osmotic pressure,
R=0.08206 L - atm/(K mol),T is
temperature, and M is molarity in moles per liter of
solution.
!!
Part B
A protein subunit from an enzyme is part of a research study and needs to be characterized.A total of 0.135 g of this subunit
was dissolved in enough water to produce 2.00 mL of solution. At 28 ° C the osmotic pressure produced by the solution was
0.138 atm. What is the molar mass of the protein?
Express your answer with the appropriate units.
> View Available Hint(s)
HA
?
Transcribed Image Text:I Review | Constants | Periodic Table The molar mass of a compound expresses the ratio of mass to moles: mass in grams Part A molar mass = number of moles tert-Butyl alcohol is a solvent with a K¡ of 9.10 °C/m and a freezing point of 25.5 °C. When 0.807 g of an upknown colorless nonelectrolyte liquid was dissolved in 11.6 g of tert-butyl alcohol, the solution froze at 15.3 C.Which of the following is most likely the identity of this unknown liquid? This quantity can be determined experimentally by accurately measuring the mass of the sample and determining the corresponding number of moles based on some property of the sample. Freezing- point depression and osmotic pressure measurements are frequently used to calculate the number of moles in solution for this type of determination. > View Available Hint(s) O ethylene glycol (molar mass = 62.07 g/mol) %3D Freezing-point depression is equal to O 1-octanol (molar mass = 130.22 g/mol) %3D AT = Kt m O glycerol (molar mass = 92.09 g/mol) where AT is the change in temperature, KĘ is the molal freezing-point-depression constant, and m is the molality in moles of solute per mass of solvent. O 2-pentanone (molar mass = 86.13 g/mol) %3D O 1-butanol (molar mass = 74.12 g/mol) Osmotic pressure is equal to II = MRT Submit where II is the osmotic pressure, R=0.08206 L - atm/(K mol),T is temperature, and M is molarity in moles per liter of solution. !! Part B A protein subunit from an enzyme is part of a research study and needs to be characterized.A total of 0.135 g of this subunit was dissolved in enough water to produce 2.00 mL of solution. At 28 ° C the osmotic pressure produced by the solution was 0.138 atm. What is the molar mass of the protein? Express your answer with the appropriate units. > View Available Hint(s) HA ?
Expert Solution
Step 1

Out of them correct ans is A

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Solutions
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781133949640
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781337399074
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781133611097
Author:
Steven S. Zumdahl
Publisher:
Cengage Learning
Chemistry: The Molecular Science
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning