Thank you so much. I had already calculated this exercise, but I thought that I did it wrong, however I get same result as you. Reason for thinking I had done it wrong is that, my teacher have answered this exercise before and the second part is different than mine and yours. I dont understand how she get the value for second part? It's so confusing
Thank you so much.
I had already calculated this exercise, but I thought that I did it wrong, however I get same result as you.
Reason for thinking I had done it wrong is that, my teacher have answered this exercise before and the second part is different than mine and yours. I dont understand how she get the value for second part? It's so confusing
![A) Vss
=
Vmax
B) Vss = Vmax
[S]O
KM + [S]O
[S]o
KM + [S]O
Vmax
nM
S
6mM
4mM + 6mM
240
nM
500
S
10s-1 * 100nM
= 400
nM
S
[S]o
6mM + [S]o
=
= Eokcat → Eo =
[S]o
=
6mM
nM
S
400:
10s-1
= 40nM](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F276c085d-4976-4cc2-ba9f-ed8f400f3309%2F4bd64338-bee3-4315-940d-23a01b5e4cc7%2F6oqogdh_processed.png&w=3840&q=75)
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Im guessing you not the same person that looked into my exercise at first. Does that mean the experts first results was incorrect and the right result is my teachers and yours?
I understand almost everything you explained, thank you. The only thing I dont understand is that how can Km be 6mM? 6mM is the substrate concentration given in part a). How can this become km
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