The ability to taste phenylthiocarbamide (PTC) is a trait controlled by a single gene with two alleles (PTC taster and PTC non-taster). Suppose 36% of a remote mountain village cannot taste PTC and must, therefore, be homozygous recessive (aa) for the PTC non-taster allele. If this population conforms to Hardy-Weinberg expectations for this gene, what percentage of the population must be homozygous (AA) for the PTC taster allele? 48% 40% 16% 32%

The ability to taste phenylthiocarbamide (PTC) is a trait controlled by a single gene with two alleles (PTC taster and PTC non-taster). Suppose 36% of a remote mountain village cannot taste PTC and must, therefore, be homozygous recessive (aa) for the PTC non-taster allele. If this population conforms to Hardy-Weinberg expectations for this gene, what percentage of the population must be homozygous (AA) for the PTC taster allele? 48% 40% 16% 32%

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter19: Population Genetics And Human Evolution

Section: Chapter Questions

Problem 12QP

See similar textbooks

Similar questions

Suppose 40 percent of people living in a remote, isolated mountain village can taste phenylthiocarbamide (PTC) and must, therefore, have at least one copy of the dominant PTC taster allele. If this population conforms to Hardy-Weinberg expectations for this gene, what percentage of the population must be heterozygous for this trait? Please explain how you got your answer.
The ability to taste the compound PTC is controlled by a dominant allele T, while individuals homozygous for the recessive allele (t) cannot taste PTC. In a population consisting of 500 individuals, 347 are tasters and 153 are non-PTC tasters. Calculate the frequency of the T and t alleles in this population, and frequency of the genotypes. (Please train yourself to use the Hardy-Weinberg equation.) To present your answers, follow the format in the picture below.
The ability to taste the compound PTC is controlled by a dominant allele T, while individuals homozygous for the recessive allele (t) cannot taste PTC. In a population consisting of 500 individuals, 347 are tasters and 153 are non-PTC tasters. Calculate the frequency of the T and t alleles in this population, and frequency of the genotypes. (Please train yourself to use the Hardy-Weinberg equation.)
Albinism is rare in most human populations, occurring at a frequency of about 1 in 20,000 people. However, the trait occurs at a frequency of 1 in 200 in certain Hopi villages of Black Mesa in Arizona. In light of this example and others that you might be aware of, what can you conclude about particular alleles such as the allele for albinism? Any allele that leads to an abnormal phenotype will be rare in most populations but common in Native American populations. Alleles that produce abnormal phenotypes are never beneficial. An allele that leads to an abnormal phenotype may be beneficial in some environments but harmful in others. An allele that leads to an abnormal phenotype will rise in frequency after many generations. An allele that leads to an abnormal phenotype will soon disappear from a population.
In a large herd of 5468 sheep, 76 animals have yellow fat, and the rest of the members of the herd have white fat. Yellow fat is inherited as a recessive trait. This herd is assumed to be in Hardy-Weinberg equilibrium. A. What are the frequencies of the white and yellow fat alleles in this population? B. Approximately how many sheep with white fat are heterozygous carriers of the yellow allele?
The ability to taste the compound PTC is controlled by a dominant allele T, while individuals homozygous for the recessive allele (t) cannot taste PTC. In a population consisting of 500 individuals, 347 are tasters and 153 are non-PTC tasters. Calculate the frequency of the T and t alleles in this population, and frequency of the genotypes.
Half of the worlds population eats rice at least twice a day. Much of this rice is grown in flooded conditions, and different strains of rice are tolerant (survive) or intolerant (die) under these conditions. Rice breeders used genetic crosses to test whether tolerance to flooding is a dominant trait. Researchers used three true-breeding flood-tolerant strains, FR143, BKNFR, and Kurk, and two true-breeding flood- intolerant strains, IR42 and NB, in the crosses. Results were obtained from three sets of crosses and are reported in the Table below: Results of cross of F1 to tolerant parent: F1 plants were crossed with the tolerant parent of the cross. Number of Plants Progeny Analyzed from Intolerant Tolerant Cross Alive Dead Total 1. F2 results of cross: IR42 FR13A 187 77 264 IR42 BKNFR 192 73 265 NB Kurk 142 52 195 2. Results of cross of F1 to intolerant parent: (F1 of IR42 FR13A) IR42 14 17 31 (F1 of IR42 BKNFR) IR42 15 10 25 (F1 of NB Kurk) NB 21 35 56 3. Results of cross of F1 to tolerant parent: (F1 of IR42 FR13A) FR13A 31 0 31 (F1 of IR42 BKNFR) BKNFR 28 0 28 (F1 of NB Kurk) Kurk 40 0 40 Do the data support the hypothesis that the tolerance trait is dominant? Justify your conclusion by explaining the results from each of the three sets of crosses in terms of genotypes and phenotypic ratios. Source: T. Setter et al. 1997. Physiology and genetics of submergence tolerance in rice. Annals of Botany 79:6777.
Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic frequencies of the MN blood group locus (see Question 2 for a description of the MN blood group) in a small human population. You find that for 1-year-old children, the genotypic frequencies are MM = 0.25, MN = 0.5, and NN = 0.25, whereas the genotypic frequencies for adults are MM = 0.3, MN = 0.4, and NN = 0.3. a. Compute the M and N allele frequencies for 1-year-olds and adults. b. Are the allele frequencies in equilibrium in this population? c. Are the genotypic frequencies in equilibrium?
A genetic mutation that causes deafness in humans has an autosomal recessive pattern of inheritance. In a study of a population of 235 Turkish children, 48 displayed the recessive phenotype. The frequency of the heterozygous genotype in the population of Turkish children described above is?
The inability to fold your tongue is an autosomal recessive trait. Assuming that the population being studied is in Hardy-Weinberg equilibrium with respect to this particular gene, what percentage of the population would be expected to be heterozygous carriers if 9% of the population is known to be homozygous recessive?
In hamsters, there is a dominant allele (S) for smooth fur and a recessive allele (s) for spiky fur. A unique characteristic of these alleles is that the heterozygote (Ss) has its own phenotype - rough fur. In this way, we can determind the number of heterozygotes in the population. In a population of 1000 hamsters, 390 have smooth fur (SS), 470 have rough fur (Ss) and 140 have spiky fur (ss). Question: The frequency of s (q) is equal to Question 1 options: 0.625 0.375 0.140 0.280
In hamsters, there is a dominant allele (S) for smooth fur and a recessive allele (s) for spiky fur. A unique characteristic of these alleles is that the heterozygote (Ss) has its own phenotype - rough fur. In this way, we can determind the number of heterozygotes in the population. In a population of 1000 hamsters, 390 have smooth fur (SS), 470 have rough fur (Ss) and 140 have spiky fur (ss). Question: The expected genotype frequency of Ss (2pq) in the next generation is expected to be: Question 2 options: 0.938 0.469 0.390 469