The angle (with respect to the vertical) of a simple pendulum is given by e = 0mcos[(4.64 rad/s)t + p]. If at t = 0,0 = 0.0350 rad and de/dt = -0.200 rad/s, what are (a) the phase constant p and (b) the maximum angle 0m? (Hint: Don't confuse the rate de/dt at which e changes with the w of the SHM.) Pivot point L. S= Le F, cose Fsine- (a) (b)

The angle (with respect to the vertical) of a simple pendulum is given by e = 0mcos[(4.64 rad/s)t + p]. If at t = 0,0 = 0.0350 rad and de/dt = -0.200 rad/s, what are (a) the phase constant p and (b) the maximum angle 0m? (Hint: Don't confuse the rate de/dt at which e changes with the w of the SHM.) Pivot point L. S= Le F, cose Fsine- (a) (b)

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter16: Oscillations

Section: Chapter Questions

Problem 34PQ: Show that angular frequency of a physical pendulum phy=mgrCM/I (Eq. 16.33) equals the angular...

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