The article "Uncertainty Estimation in Railway Track Life-Cycle Cost"t presented the following data on time to repair (min) a rail break in the high rail on a curved track of a certain railway line.15912048014927054734043228202240218n USE SALTA normal probability plot of the data shows a reasonably linear pattern, so it is plausible that the population distribution of repair time is at least approximately normal. The sample mean and standard deviation are 249.7 and 145.1, respectively.(a) Is there compelling evidence for concluding that true average repair time exceeds 200 min? Cary out a test of hypotheses using a significance level of 0.05.State the appropriate hypotheses.Ο H: μ= 200Hai u > 200Но: и < 200Ha: u = 200Но: и 3 200H: u + 200Но: и 3 200H2: u < 200Ho: u > 200Ha: u = 200Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.)t =P-value =What can you conclude?There is compelling evidence that the true average repair time exceeds 200 min.There is not compelling evidence that the true average repair time exceeds 200 min.(b) Using o = 150, what is the type II error probability of the test used in (a) when true average repair time is actually 300 min? That is, what is B(300)? (Round your answer to two decimal places. You will need to use the appropriate table in theAppendix of Tables to answer this question.)B(300) =

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Description: The article "Uncertainty Estimation in Railway Track Life-Cycle Cost"t presented the following data on time to repair (min) a rail break in the high rail on a curved track of a certain railway line.15912048014927054734043228202240218n USE SALTA norm

Given observation 159 120 480 149 270 547 340 43 228 202 240 218

The article "Uncertainty Estimation in Railway Track Life-Cycle Cost"t presented the following data on time to repair (min) a rail break in the high rail on a curved track of a certain railway line. 159 120 480 149 270 547 340 43 228 202 240 218 IA USE SALT A normal probability plot of the data shows a reasonably linear pattern, so it is plausible that the population distribution of repair time is at least approximately normal. The sample mean and standard deviation are 249.7 and 145.1, respectively. (a) Is there compelling evidence for concluding that true average repair time exceeds 200 min? Carry out a test of hypotheses using a significance level of 0.05. State the appropriate hypotheses. • Hoi H- 200 H:H > 200 O Hoi H< 200 H:- 200 O Hoi - 200 H: 200 O Ho: H- 200 H:H< 200 O Ho: H > 200 H:- 200 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) P-value - What can you conclude? O There is compelling evidence that the true average repair time exceeds 200 min. O There is not compelling evidence that the true average repair time exceeds 200 min. (b) Using a- 150, what is the type II error probability of the test used in (a) when true average repair time is actually 300 min? That is, what is B(300)? (Round your answer to two decimal places. You will need to use the appropriate table in the Appendix of Tables to answer this question.) B(300) -

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Author:Amos Gilat

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The article "Uncertainty Estimation in Railway Track Life-Cycle Cost"t presented the following data on time to repair (min) a rail break in the high rail on a curved track of a certain railway line.
159
120
480
149
270
547
340
43
228
202
240
218
n USE SALT
A normal probability plot of the data shows a reasonably linear pattern, so it is plausible that the population distribution of repair time is at least approximately normal. The sample mean and standard deviation are 249.7 and 145.1, respectively.
(a) Is there compelling evidence for concluding that true average repair time exceeds 200 min? Cary out a test of hypotheses using a significance level of 0.05.
State the appropriate hypotheses.
Ο H: μ= 200
Hai u > 200
Но: и < 200
Ha: u = 200
Но: и 3 200
H: u + 200
Но: и 3 200
H2: u < 200
Ho: u > 200
Ha: u = 200
Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.)
t =
P-value =
What can you conclude?
There is compelling evidence that the true average repair time exceeds 200 min.
There is not compelling evidence that the true average repair time exceeds 200 min.
(b) Using o = 150, what is the type II error probability of the test used in (a) when true average repair time is actually 300 min? That is, what is B(300)? (Round your answer to two decimal places. You will need to use the appropriate table in the
Appendix of Tables to answer this question.)
B(300) =

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