The average number of hours of relief provided by 5 different tablets are as follows: Tablet 1 Tablet 2 Tablet 3 Tablet 4 Tablet 5 5 9 3 2 7 4 7 5 3 8. 8 2 4 9. 3 1 4 3 9 7 4 7 T = 26 T, = 39 T, = 20 T, =14 T = 33 NOTE: x =834 The ANOVA table shown below is partially completed with the information in the table above. The data is from five different tablets (independent populations) that are normally distributed with equal variances. Degrees of Freedom Sum of Squares Mean Square F Treatment 79.440 Error Total 24 a) Fill in the missing values and complete the ANOVA table. b) Using the information from the table above test whether there is a significant difference in the average number of hours of relief provided by the tablets differ for at least 2 of the brands. Use a =0.05
The average number of hours of relief provided by 5 different tablets are as follows: Tablet 1 Tablet 2 Tablet 3 Tablet 4 Tablet 5 5 9 3 2 7 4 7 5 3 8. 8 2 4 9. 3 1 4 3 9 7 4 7 T = 26 T, = 39 T, = 20 T, =14 T = 33 NOTE: x =834 The ANOVA table shown below is partially completed with the information in the table above. The data is from five different tablets (independent populations) that are normally distributed with equal variances. Degrees of Freedom Sum of Squares Mean Square F Treatment 79.440 Error Total 24 a) Fill in the missing values and complete the ANOVA table. b) Using the information from the table above test whether there is a significant difference in the average number of hours of relief provided by the tablets differ for at least 2 of the brands. Use a =0.05
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Transcribed Image Text:The average number of hours of relief provided by 5 different tablets are as
follows:
Tablet 1 Tablet 2 Tablet 3 Tablet 4 Tablet 5
5
9
3
2
7
4
7
3
6.
8.
8.
4
6.
6.
3
1
4
3
9.
7
4
T = 26
T, = 39
T = 20
T =14
T
=33
%3D
%3D
NOTE: Ex =834
The ANOVA table shown below is partially completed with the information in the table
above. The data is from five different tablets (independent populations) that are normally
distributed with equal variances.
Degrees of
Freedom
Sum of Squares
Mean Square
F
Treatment
79.440
Error
Total
24
a) Fill in the missing values and complete the ANOVA table.
b) Using the information from the table above test whether there is a significant
difference in the average number of hours of relief provided by the tablets differ for at
least 2 of the brands. Use a =
0.05
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