The catalytic decomposition of hydrogen peroxide yields oxygen gas and water, according to the reaction given below. In an experiment, the decomposition of hydrogen peroxide yielded 75.3 mL of gas collected over water at 25°C and 0.976 atm. (Pwater = 0.032 atm at 25°C)2 H2O2(aq) → 2 H2O(l) + O2(g)If the original H2O2 solution had a volume on 500 mL, what was the molar concentration of hydrogen peroxide prior to decomposition?

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Asked Dec 10, 2019
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The catalytic decomposition of hydrogen peroxide yields oxygen gas and water, according to the reaction given below. In an experiment, the decomposition of hydrogen peroxide yielded 75.3 mL of gas collected over water at 25°C and 0.976 atm. (Pwater = 0.032 atm at 25°C)

2 H2O2(aq) → 2 H2O(l) + O2(g)

If the original H2O2 solution had a volume on 500 mL, what was the molar concentration of hydrogen peroxide prior to decomposition? 

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Expert Answer

Step 1

Given,

Volume of gas, O2 collected over water, V = 75.3 mL = 0.0753 L   (1 mL = 0.001 L)

Temperature, T = 25°C = 273 + 25 = 298 K

Total pressure, Ptotal = 0.976 atm

Vapour pressure of water at 25°C, Pwater = 0.032 atm

Original volume of H2O2 solution = 500 mL = 0.5 L

The pressure of gas, O2 can be calculated from Dalton\'s Law of Partial Pressures, which states :

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Ptotal = Pgas +Pwater Pgas = Ptotal – Pwater Pgas = 0.976 atm – 0.032 atm Pgas = 0.944 atm

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Step 2

The moles of gas, O2 can be calculated using the ideal gas equation as :

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Pgas V = ngas R T Pgas V Ngas RT 0.944 atm × 0.0753 L Ngas L atm x 298 K 0.0821 mol K ngas = 0.003 mol

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Step 3

The catalytic decomposition of hydrogen peroxide yields ox...

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1 mol O2 requires → 2 mol H2O2 2 mol H202 1 mol O2 :. 0.003 mol O2 requires x 0.003 mol O2 = 0.006 mol H2O2

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Alcohols, phenols and ether

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