The equilibrium constant for the binding of a drug molecule to a protein was measured as 200. In a separate experiment, the rate constant for the binding process, which is second order overall, was found to be 1.5 × 108 dm3 mol–1 s–1. What is the rate constant for the first-order dissociation of the drug molecule from the protein–drug complex?
The equilibrium constant for the binding of a drug molecule to a protein was measured as 200. In a separate experiment, the rate constant for the binding process, which is second order overall, was found to be 1.5 × 108 dm3 mol–1 s–1. What is the rate constant for the first-order dissociation of the drug molecule from the protein–drug complex?
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter13: Chemical Kinetics
Section: Chapter Questions
Problem 13.42QE
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The equilibrium constant for the binding of a drug molecule to a protein was measured as 200. In a separate experiment, the rate constant for the binding process, which is second order overall, was found to be 1.5 × 108 dm3 mol–1 s–1. What is the rate constant for the first-order dissociation of the drug molecule from the protein–drug complex?
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