The equilibrium constant for the reaction C6H5COOH(aq) + CH3COO"(aq) s C6H5CO0¯(aq) + CH3COOH(aq) is 3.6 at 25°C. If Ka for CH3COOH is 1.8 × 10-5, what is the acid dissociation constant for C6H5COOH?

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter15: Acid–base Equilibria
Section: Chapter Questions
Problem 7P
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Answer: 6.5 x 10-5 (Can you explain?)

The equilibrium constant for the reaction
C6H5COOH(aq) + CH3COO (aq) = C6H5CO0(aq) + CH3COOH(aq)
is 3.6 at 25°C. If Ką for CH3COOH is 1.8 × 10-5, what is the acid dissociation constant for C6H5COOH?
Transcribed Image Text:The equilibrium constant for the reaction C6H5COOH(aq) + CH3COO (aq) = C6H5CO0(aq) + CH3COOH(aq) is 3.6 at 25°C. If Ką for CH3COOH is 1.8 × 10-5, what is the acid dissociation constant for C6H5COOH?
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