The equilibrium constant, K,, for the following reaction is 2.74 at 1.15x103K. 2503(g) 2s02(9) + 02(9) If an equilibrium mixture of the three gases in a 16.5 L container at 1.15×103K contains Soz at a pressure of 1.62 atm and So, at a pressure of 1.04 atm, the equilibrium partial pressure of 0, is atm.

Principles of Modern Chemistry
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Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
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Chapter14: Chemical Equilibrium
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The equilibrium constant, K,, for the following reaction is 2.74 at 1.15x1o3K.
2503(g) 2s02(g) + 02(g)
If an equilibrium mixture of the three gases in a 16.5 L container at 1.15×103K contains soz at a pressure of 1.62 atm and So, at a pressure of 1.04 atm, the equilibrium partial pressure of O, is
atm.
Transcribed Image Text:The equilibrium constant, K,, for the following reaction is 2.74 at 1.15x1o3K. 2503(g) 2s02(g) + 02(g) If an equilibrium mixture of the three gases in a 16.5 L container at 1.15×103K contains soz at a pressure of 1.62 atm and So, at a pressure of 1.04 atm, the equilibrium partial pressure of O, is atm.
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