The figure shows a circuit containing an electromotive force, a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (0). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case we use the Kirchhoff's Law. RI +8 - E(0) But I= dQ/dt, so we have the formula below. Suppose the resistance is 20 , the capacitance is 0.01 F, and a battery gives a constant voltage of 100 V.
The figure shows a circuit containing an electromotive force, a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (0). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case we use the Kirchhoff's Law. RI +8 - E(0) But I= dQ/dt, so we have the formula below. Suppose the resistance is 20 , the capacitance is 0.01 F, and a battery gives a constant voltage of 100 V.
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter29: Direct Current (dc) Circuits
Section: Chapter Questions
Problem 72PQ: A capacitor with initial charge Q0 is connected across a resistor R at time t = 0. The separation...
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