In the following circuit, the voltage source Vdc is supplying 65.23 V. The switch S, remains close and S, remains open for a long time priorto time t=0. Then at time t = 0, the switch S, becomes open and S2 becomes closed. Determine, the time constant (in seconds) of thecircuit, if the voltage across the 65.23 mF capacitor is valt).30 kn30 knVác+S215 koCxVc(t)

Answered: Image /qna-images/answer/a98fccab-23c4-4d82-bb5f-8e244360917b.jpg

Answered: the following circuit, the voltage…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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In the circuit given below, the switch is closed at t <0 and the system works continuously. At t-0 the switch is opened, calculate the value of the voltage (Va) of point a at t = 1 ms.
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In the circuit shown, the switch is inthe closed position for a long timebefore it opens at time ? = 0.A. Find the differentialequation satisfied by the outputvoltage, v0(t) for t> 0. B. the initial conditions for this circuit are: v0(0+) = 0 and dv0/dt(0+) =−30,000 V/s. .findv0(t) for t > 0.
The current i(t) in an RL circuit is governed by the differential equation di/dt + R/L i = 1/L (E(t)), where R and L are constants and E(t) represents the applied EMF. At t = 0, the switch in the circuit isclosed, and the applied EMF increases linearly from 0 V to 10 V in a time interval of 5 seconds. The EMF thenremainsconstantfort ≥5.Determinethecurrent in the circuit for t ≥0.
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