The following is a nucleophilic substitution reaction of S-3-chloro-2-methylhexane with "CN. The experimental rate law for this reaction is Rate = k [S-3-chloro-2-methylhexane] CH3 H,C. H CH, + CEN H2 The mechanism for this reaction is Sy1
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- The following alcohols react with HBr to afford an alkyl bromide. Based on their structures, indicate if the reaction mechanism is likely to be Sn1 or Sn23-methyl-2-butanol forms 2-bromo-2-methylbutane as a single product with HBr. This reactionWrite down the mechanism.As in the free-radical halogenation of alkanes, chlorination of alkylbenzenes is less selective than bromination. Given the relative rates per hydrogen for hydrogen atom abstraction from 1-phenylbutane by chlorine for the elementary step shown, calculate the percentage of 1-chloro-1-phenylbutane in the C10H13Cl product.
- Predict the products and mechanisms of the following reactions. When more than oneproduct or mechanism is possible, explain which are most likely. ) 1@bromo@1@methylcyclopentane + NaOEt in ethanolThe rate law for the reaction of HO- with tert-butyl bromide to form an elimination product in 75% ethanol/ 25% water at 30 °C is the sum of the rate laws for the E2 and E1 reactions. What percentage of the reaction takes place by an E2 pathway when [HO-] = 5.0 M? (k2 = 7.1 x 10-5, and k1 = 1.5 x 10-5)1 – Show the complete mechanism, using arrows to show electron movement, for the free radical chlorination of cyclopentane. The products are chlorocyclopentane and HCl. Be sure to include the initiation, propagation, and termination steps.
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