2A + 20 -> F + 2E Step 1: A + A <->B k/k1 (very very fast) Step 2: B + C->D+E k2 (fast) Step 3: D+ C-> E+ F k3 (slow) Using steady state approximation, derive the rate law from the reaction mechanism above.

2A + 20 -> F + 2E Step 1: A + A <->B k/k1 (very very fast) Step 2: B + C->D+E k2 (fast) Step 3: D+ C-> E+ F k3 (slow) Using steady state approximation, derive the rate law from the reaction mechanism above.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter30: Kinetic Methods Of Analysis

Section: Chapter Questions

Problem 30.6QAP

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Question

Given the reaction below and its reaction mechanism:
2A + 20 -> F + 2E
Step 1: A + A <-> B kj/k1 (very very fast)
Step 2: B+ C ->D+E_ k2 (fast)
Step 3: D + C-> E+ F k3 (slow)
Using steady state approximation, derive the rate law from the reaction mechanism above. (Upload a picture or file of your solution)
A -
В I
= E EE
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