The mechanism for the reaction between 2-chloroethanol , CH2CICH2OH, and hydroxide ions in aqueous solution to form ethylene oxide, (CH2CH2)O, is thought to consist of two steps(1) CH2CICH2OH + OH-= CH2CICH2O- + H2O fast(2) CH2CICH2O- = (CH2CH2)O + CI- slowShow that, for this mechanism, the rate of formation of ethylene oxide is Rate= k2 K[CH2CICH2OH][OH-]where K is the equilibrium constant for the first step and k2 is the rate constant for the second step.

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Answered: The mechanism for the reaction between…

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter13: Chemical Kinetics

Section: Chapter Questions

Problem 13.50QE

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The mechanism for the reaction between 2-chloroethanol , CH₂CICH₂OH, and hydroxide ions in aqueous solution to form ethylene oxide, (CH₂CH₂)O, is thought to consist of two steps
(1) CH₂CICH₂OH + OH^-= CH₂CICH₂O^- + H₂O fast
(2) CH₂CICH₂O^-= (CH₂CH₂)O + CI^-slow
Show that, for this mechanism, the rate of formation of ethylene oxide is
Rate= k₂ K[CH₂CICH₂OH][OH^-]

where K is the equilibrium constant for the first step and k₂ is the rate constant for the second step.

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