The following net ionic equation represents the reaction between the hydrogen phthalate ion, HC8H4O4–, and hydroxide ion.                HC8H4O4–(aq)  +  OH–(aq)  -->  C8H4O42–(aq)  +  H2O(l)    A 40.0 mL solution of 0.100 M potassium hydrogen phthalate, KHC8H4O4, is titrated with 0.100 M NaOH. After 50.0% of the molar quantity of the hydrogen phthalate ion, HC8H4O4–, is reacted and converted to its conjugate base, the resulting solution is found to have a pH of 5.398. What is the Ka of the hydrogen phthalate ion, HC8H4O4– ?             (A) 4.00 x 10–5           (B) 4.00 x 10–6           (C) 2.50 x 10–9           (D) 1.60 x 10–10

Principles of Modern Chemistry
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Chapter11: Solutions
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Problem 26P
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The following net ionic equation represents the reaction between the hydrogen phthalate ion, HC8H4O4, and hydroxide ion.

               HC8H4O4(aq)  +  OH(aq)  -->  C8H4O42–(aq)  +  H2O(l)

   A 40.0 mL solution of 0.100 M potassium hydrogen phthalate, KHC8H4O4, is titrated with 0.100 NaOH. After 50.0% of the molar quantity of the hydrogen phthalate ion, HC8H4O4, is reacted and converted to its conjugate base, the resulting solution is found to have a pH of 5.398. What is the Ka of the hydrogen phthalate ion, HC8H4O4– ?  

          (A) 4.00 x 10–5

          (B) 4.00 x 10–6

          (C) 2.50 x 10–9

          (D) 1.60 x 10–10

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