The formation of helium nucleus, from the fusion process of two deuterium nuclei is shown as below: 21H + 21H → 32He + 10n + energy Based on Equation above, which of the following statements is true? a)Binding energy per nucleon of 32He is equal to zero. b)Binding energy per nucleon of 32He is higher than the binding energy per nucleon of 21H c) Binding energy per nucleon of 21H is higher than the binding energy per nucleon of 32He d) Binding energy per nucleon of 32He is equal to the binding energy per nucleon of 21H
The formation of helium nucleus, from the fusion process of two deuterium nuclei is shown as below: 21H + 21H → 32He + 10n + energy Based on Equation above, which of the following statements is true? a)Binding energy per nucleon of 32He is equal to zero. b)Binding energy per nucleon of 32He is higher than the binding energy per nucleon of 21H c) Binding energy per nucleon of 21H is higher than the binding energy per nucleon of 32He d) Binding energy per nucleon of 32He is equal to the binding energy per nucleon of 21H
Chapter19: The Nucleus: A Chemist's View
Section: Chapter Questions
Problem 7RQ
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Question
The formation of helium nucleus, from the fusion process of two deuterium nuclei is shown as below:
21H
+
21H
→
32He
+
10n
+ energy
Based on Equation above, which of the following statements is true?
a)Binding energy per nucleon of
32He
is equal to zero.
b)Binding energy per nucleon of
32He
is higher than the binding energy per nucleon of
21H
c) Binding energy per nucleon of
21H
is higher than the binding energy per nucleon of
32He
d) Binding energy per nucleon of
32He
is equal to the binding energy per nucleon of
21H
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