The Keq for the reaction of water with water is called KwH2O + H2O ⇔ H3O+1 + OH-1 [H3O+1][OH-1] Kw = ––––––––––––– = [H3O+1][OH-1] = (1 x 10-7)2 = 1 x 10-14 [H2O]2 The inverse logarithm, or -log, of [H3O*][OH1] = 10-14 is pH + pOH = 141. What happens to the [H30*1] when acid is added to neutral water ?the [H3O*'] goes2. What happens to the pH when acid is added to neutral water ?an example of an increased [H30*l] is [H30*l]=1 x 10-6. Thus pH = -log[10ʻ] = 6thus, adding acid makes the pH go3. What happens to the [OH'] when acid is added to neutral water ?in the equation [H3O+'][OH´1] = 10-14, when [H3O*1] increases, the [OH1] goes4. What happens to the pOH when acid is added to neutral water ?when [OH-'] decreases, the pOH goessince the pOH = -log[OH1]this can also be seen using pH + pOH = 145. What happens to the Kw when acid is added to neutral water ?because it's a constant.a. downb. upc. no change

Water has many unique properties that make it very special and important for life on earth. The…

The inverse logarithm, or -log, of [H3O*l][OH*l] = 10*14 is pH + pOH = 14 1. What happens to the [H3O*'] when acid is added to neutral water ? the [H3O*']goes 2. What happens to the pH when acid is added to neutral water ? an example of an increased [H3O*l] is [H3O*l] = 1 x 10-6. Thus pH = -log[10-6] = 6 thus, adding acid makes the pH go 3. What happens to the [OH-'] when acid is added to neutral water ? in the equation [H3O*'][OHl] = 10-14, when [H3O*l] increases, the [OH'] goes 4. What happens to the pOH when acid is added to neutral water ? when [OH] decreases, the pOH goes since the pOH = -log[OH¨'] this can also be seen using pH + pOH = 14 5. What happens to the Kw when acid is added to neutral water ? because it's a constant. a. down b. up c. no change

The inverse logarithm, or -log, of [H3Ol][OHl] = 1014 is pH + pOH = 14 1. What happens to the [H3O'] when acid is added to neutral water ? the [H3O']goes 2. What happens to the pH when acid is added to neutral water ? an example of an increased [H3Ol] is [H3Ol] = 1 x 10-6. Thus pH = -log[10-6] = 6 thus, adding acid makes the pH go 3. What happens to the [OH-'] when acid is added to neutral water ? in the equation [H3O'][OHl] = 10-14, when [H3O*l] increases, the [OH'] goes 4. What happens to the pOH when acid is added to neutral water ? when [OH] decreases, the pOH goes since the pOH = -log[OH¨'] this can also be seen using pH + pOH = 14 5. What happens to the Kw when acid is added to neutral water ? because it's a constant. a. down b. up c. no change

Principles Of Pharmacology Med Assist

6th Edition

ISBN:9781337512442

Author:RICE

Publisher:RICE

Chapter3: Ratio And Proportion

Section: Chapter Questions

Problem 1RP

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