The only question I need to answer is the final one about APA. If you could let me know if the rest of my current answers look right, that would be awesome too. 3. A medical researcher examined the number of asthma attacks patients had both before and while using an advanced air purifier. Seven patients were included in the study. The number of asthma attacks for each patient before and during using the air purifier is reported below. Use α = .05, 2-tailed. Patient Before Purifier During Purifier 1 5 6 2 8 7 3 11 7 4 6 4 5 7 5 6 7 6 7 5 4 a. State the null and alternative hypotheses below. Null Hypothesis There is no difference H0: µd=0 Alternative Hypothesis There is a different amount of asthma attacks when using an advanced air purifier. µd ≠ 0 b. What type of test should be run on the data (be specific with the exact name of the test)? For example, don’t just state “t test,” but the specific t test used. Paired T-test c. What is the conclusion of the hypothesis test? State the p-value and the decision about the hypothesis test below. (Don’t write the results here – that will be done in (e) below – just state p and whether H0 is rejected.) We reject the alternative hypothesis. p-value = 0.5723 d. What is the effect size for the study? (1) Calculate and report the effect size below. (2) Indicate the magnitude of the effect size according to Cohen’s standards and (3) interpret what the effect size means in terms of standard deviation units. The p-value using SPSS is 0.5723 The level of significance is 0.05. The p-value is, 0.5723 > 0.05. We reject the alternative hypothesis. p-value = 0.5723 > 0.05. We reject the alternative hypothesis, we conclude that there is no significant difference before and after using a purifier. e. Write the results of the test in APA format below. (Hint: This type of write-up would be structured in a similar fashion to what you see in your text.)
The only question I need to answer is the final one about APA. If you could let me know if the rest of my current answers look right, that would be awesome too.
3. A medical researcher examined the number of asthma attacks patients had both before and while using an advanced air purifier. Seven patients were included in the study. The number of asthma attacks for each patient before and during using the air purifier is reported below. Use α = .05, 2-tailed.
|
Patient |
Before Purifier |
During Purifier |
|
1 |
5 |
6 |
|
2 |
8 |
7 |
|
3 |
11 |
7 |
|
4 |
6 |
4 |
|
5 |
7 |
5 |
|
6 |
7 |
6 |
|
7 |
5 |
4 |
a. State the null and alternative hypotheses below.
Null Hypothesis
There is no difference
H0: µd=0
Alternative Hypothesis
There is a different amount of asthma attacks when using an advanced air purifier.
µd ≠ 0
b. What type of test should be run on the data (be specific with the exact name of the test)? For example, don’t just state “t test,” but the specific t test used.
Paired T-test
c. What is the conclusion of the hypothesis test? State the p-value and the decision about the hypothesis test below. (Don’t write the results here – that will be done in (e) below – just state p and whether H0 is rejected.)
We reject the alternative hypothesis.
p-value = 0.5723
d. What is the effect size for the study? (1) Calculate and report the effect size below. (2) Indicate the magnitude of the effect size according to Cohen’s standards and (3) interpret what the effect size means in terms of standard deviation units.
The p-value using SPSS is 0.5723
The level of significance is 0.05.
The p-value is, 0.5723 > 0.05.
We reject the alternative hypothesis.
p-value = 0.5723 > 0.05.
We reject the alternative hypothesis, we conclude that there is no significant difference before and after using a purifier.
e. Write the results of the test in APA format below. (Hint: This type of write-up would be structured in a similar fashion to what you see in your text.)
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
