The reaction of sulfuric acid (H2SO4) with potassium hydroxide (KOH) is described by the equation: H2SO4 + 2KOH → K2SO4 + 2H2O Suppose 50 mL of KOH with unknown concentration is placed in a flask with bromthymol blue indicator. A solution of 0.10 M H2SO4 is dripped into the KOH solution. After exactly 33.4 mL of H2SO4 is added, the indicator changes from blue to yellow. What is the concentration of the KOH? 0.067 M 0.13 M 0.15 M 0.26 M
The reaction of sulfuric acid (H2SO4) with potassium hydroxide (KOH) is described by the equation: H2SO4 + 2KOH → K2SO4 + 2H2O Suppose 50 mL of KOH with unknown concentration is placed in a flask with bromthymol blue indicator. A solution of 0.10 M H2SO4 is dripped into the KOH solution. After exactly 33.4 mL of H2SO4 is added, the indicator changes from blue to yellow. What is the concentration of the KOH? 0.067 M 0.13 M 0.15 M 0.26 M
Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 96AE: One method for determining the purity of aspirin (C9H8O4) is to hydrolyze it with NaOH solution and...
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The reaction of sulfuric acid (H2SO4) with potassium hydroxide (KOH) is described by the
equation:
H2SO4 + 2KOH → K2SO4 + 2H2O
Suppose 50 mL of KOH with unknown concentration is placed in a flask with bromthymol blue indicator. A solution of 0.10 M H2SO4 is dripped into the KOH solution. After exactly 33.4 mL of H2SO4 is added, the indicator changes from blue to yellow. What is the concentration of the KOH?
- 0.067 M
- 0.13 M
- 0.15 M
- 0.26 M
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