The rigid bar A,B,C,D shown in figure is connected to the ground by a hinge at B and to Magnesium bar at A, Aluminum bar at C. the properties of the bars are shown on the figure. all the connections are using 16 mm bolts in single shear. Determine the maximum safe load W that can be applied. Determine the final position of point D.
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- Repeat Problem 11.2-3 assuming that R= 10 kN · m/rad and L = 2 m.A scuba t a n k (see fig ure) i s bci ng d e signed fo r an internal pressure of 2640 psi with a factor of safety of 2,0 with respect to yielding. The yield stress of the steel is 65,000 psi in tension and 32,000 psi in shear, (a) If the diameter of the tank is 7,0 in., what is the minimum required wall thickness? (b) If the wall thickness is 0.25 in., what is the maximum acceptable internal pressure?In the Bolted Connection shown, find the following by ASD.Specifications:M20 Bolts in standard holes. Nominal hole diameter = 22mmEffective Hole diameter = nominal hole diameter + 2 mmA325 steel boltAssume thread in shear planeFv = 372 MPaProperties of Angle Bar< 125 x 125 x 13 mmA = 3065 mm²x = 36.3 mmy = 36.3 mmFy = 248 MPa , Fu = 410 MPa 1. For angle bars used as bolted tension element connected to another element only on one leg, the effective area Ae = UAn. Where: An = Net area, U = Shear lag factor = 1 – x/L, L= center to center longitudinal distance of extremely located fasteners, X= distance from centroid of angle bar to surface of contact of joined elements. What is the shear lag factor of our angular bar? a. 0.454 b. 0.9 c. 0.838 d. 0.869 2. Considering RUPTURE of angle bar, what is the allowable force P that the connection can handle if allowable RUPTURE stress in net area of angle bar is Fu/2 a. 463.83 kN…
- A semi-elliptic spring used for automobile suspension, consists of two extra full-length leaves and eight graduated-length leaves, including the master leaf. The centre-to centre distance between the two eyes is 1 m. The leaves are made of steel 55Si2Mo90 (Syt = 1500 N/mm2and E = 207000 N/mm2) and the factor of safety is 2. The maximum spring load is 30 kN. The leaves are pre- stressed so as to equalize stresses in all leaves under maximum load. Determine the dimensions of the cross-section of the leaves and the deflection at the end of the spring.An 02-seris single-row deep-groove ball bearing with a 90 mm bore (C0 = 62 kN, C10 = 95.6 kN) is loaded with a 4.34 kN axial load and a 10 kN radial load. The inner ring rotates at 600 rpm (v=1). What is the FaC0? Should X1/Y1 or X2/Y2 be used to caculate the equivalent radial load? Determine the equivalent radial load experienced by this bearing. What is the bearing’s in-use reliability, assuming a design life of 2*10^8 revolutions and an application factor of 1.2?A semi-elliptic spring used for automobile suspension, consists of twoextra full-length leaves and eight graduated-length leaves, including themaster leaf. The centre-to-centre distance between the two eyes is 1 m.The leaves are made of steel 55Si2Mo90 (S = 1500 N/mm yt2 andE = 207 000 N/mm2) and the factor of safety is 2. The maximum springload is 30 kN. The leaves are pre-stressed so as to equalize stresses in allleaves under maximum load. Determine the dimensions of thecross-section of the leaves and the deflection at the end of the spring.
- Thory of machine: Select one of the following bearing for the load conditions. Radial load, F=3000 N, Axial load, F = 1600 N, RPM = 1000. (1) Deep Groove ball bearing dynamic load rating=47000 N radial bad factor, X=0.56 Axial load factor, Y= 1.83 (i) Cylindrical roller bearing Dynamic load rating 28000 N radial load factor, X=1.0 axial load factor, Y=0.0A flange coupling connects two 2” diameter shafts. The flanges are fitted with 6 bolts of SAE 1040 steel on a 7” bolt circle. The shafts runs at 300 rpm and transmits 45 hp. Assume a factor of safety of 5, ultimate tension of 70,000 psi, and ultimate shear of 55,000 psi. Determine: a) The torque transmitted, in-lbs b) The force applied per bolt, lbs c) The diameter of the bolt required, in d) The thickness of flanged to be used, inDraw FBD and determine Stress and Safety Factor of Bicycle Axle (Thru Axel) Specification Weight of cyclist = 120 kg. Materials: Aluminum alloy (AL 6061-T6) Dimension: Length = 122 mm, Diameter = 12 mm, Thread pitch = 1.75 mm, Thread Length = 16 mm.
- A mild steel shaft has to transmit 75 kW at 200 rpm. Design a cast Iron flange coupling for the shaft. The allowable stresses are Shear stress for the shaft and keys 40 N/mm²Shear stress for bolts = 28 N/mm²Shear stress for C.I. coupling = 20 N/mm² Take wearing stress as twice the shear stress value and number of bolts for coupling as 6.A 0.5-in.-diameter steel [E= 30,000 ksi] bolt (1) is placed in a copper tube (2). The copper [E= 16,000 ksi] tube has an outside diameter of 1.00 in., a wall thickness of 0.125 in., and a length of L= 8.0 in. Rigid washers, each with a thickness of t= 0.125 in., cap the ends of the copper tube. The bolt has 20 threads per inch. This means that each time the nut is turned one complete revolution, the nut advances 0.05 in. (i.e., 1/20 in.). The nut is hand-tightened on the bolt until the bolt, nut, washers, and tube are just snug, meaning that all slack has been removed from the assembly but no stress has yet been induced. What stresses are produced in the bolt and in the tube if the nut is tightened an additional quarter turn past the snug-tight condition?Mechanical design The maximum load in a rotating shaft is subjected to bending moment of 1 kN.m and a torque of 1 kN.m. The member is made of steel the Ultimate Tensile Strength 440 MPa, Yield Tensile Strength 370 MPa. With a safety factor of 4, kt = km = 1.5 and keyway stress consternation is presented. According to the maximum shear stress theory, the shaft diameter will be: a. 160 mm b. 74 mm C. 145 mm d. 92.5 mm e. 60 mm f. 66 mm