The rotor of a turbine 15 kg in mass, is supported at the midspan of a shaft as shown in figure. The shaft rotates at 500 rpm and the rotor displaces by an additional of 0.01 mm. The eccentricity (e) of the rotor is (Assume simply supported shaft) Rotor Shaft E= 2.1 × 1011 N/m2 I= 7854 mm4 500mm (a) 144 um (b) 0.69 um (c) 14.4 um (d) 6.9 um

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter2: Axially Loaded Members
Section: Chapter Questions
Problem 2.8.6P
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The rotor of a turbine 15 kg in mass, is supported at the midspan of a shaft as shown in figure.
The shaft rotates at 500 rpm and the rotor displaces by an additional of 0.01 mm. The eccentricity
(e) of the rotor is
(Assume simply supported shaft)
Rotor
Shaft
E= 2.1 × 1011 N/m2
I= 7854 mm4
500 mm
(a) 144 um
(b) 0.69 um
(c) 14.4 pmn
(d) 6.9 um
Transcribed Image Text:The rotor of a turbine 15 kg in mass, is supported at the midspan of a shaft as shown in figure. The shaft rotates at 500 rpm and the rotor displaces by an additional of 0.01 mm. The eccentricity (e) of the rotor is (Assume simply supported shaft) Rotor Shaft E= 2.1 × 1011 N/m2 I= 7854 mm4 500 mm (a) 144 um (b) 0.69 um (c) 14.4 pmn (d) 6.9 um
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