The silver ion in a 25.00-mL sample was converted to dicyanoargentate (1) ion by the addition of an excess solution containing Ni(CN),²: Ni(CN)42 + 2 Ag → 2Ag(CN)21 + Ni2 The liberated nickel ion was titrated with 43.77-mL of 0.02408M EDTA. Calculate the molar concentration of the silver solution. Molar Masses: Ni = 58.69 Ag 107.9 %3!

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