"The US Centers for Disease Control and Prevention said about 72 million Americans-nearly one out of every four of the country's 304 million residents-are considered obese. Millions more are designated as overweight." The American trend toward obesity has prompted many physicians to offer weight-loss programs to their patients. [Source: Price, W. T. "Physicians Get into the Weight-Loss Business." Florida Today, July 7, 2008.] A physician conducted an experimental study to compare the effectiveness of four different weight-loss programs. In the study, 60 obese adults were randomly assigned to the four programs so that each program had 15 adults. The programs lasted for six months. The weights of the subjects were measured before and after the programs, and each subject's weight loss was computed in pounds. The following table summarizes the results of the study, giving the number of observations and the sample mean and variance of the subjects' weight loss in each program. Treatment Number of Observations, n Sample Mean, M (Pounds) Sample Variance, s? (Pounds squared) Program A 15 17.9 99.7 Program B 15 19.5 95.7 Program C 15 10.2 99.7 Program D 15 22.1 100.6 The physician selects a significance level of a = 0.05. Why should she perform an analysis of variance (ANOVA) with a = 0.05 instead of simply using multiple t tests with a = 0.05 to compare the six pairs of group means? An ANOVA avoids the problem of an inflated experimentwise alpha level. An ANOVA avoids the problem of an inflated testwise alpha level. The probability of a Type I error when performing multiple t tests at a = 0.05 will be less than 0.05. Multiple t tests at a = 0.05 result in an experimentwise alpha level smaller than a = 0.05.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 25PPS
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"The US Centers for Disease Control and Prevention said about 72 million Americans-nearly one out of every four of the country's 304 million
residents-are considered obese. Millions more are designated as overweight." The American trend toward obesity has prompted many physicians to
offer weight-loss programs to their patients. [Source: Price, w. T. "Physicians Get into the Weight-Loss Business." Florida Today, July 7, 2008.]
A physician conducted an experimental study to compare the effectiveness of four different weight-loss programs. In the study, 60 obese adults were
randomly assigned to the four programs so that each program had 15 adults. The programs lasted for six months. The weights of the subjects were
measured before and after the programs, and each subject's weight loss was computed in pounds.
The following table summarizes the results of the study, giving the number of observations and the sample mean and variance of the subjects' weight
loss in each program.
Treatment
Number of Observations, n
Sample Mean, M (Pounds) Sample Variance, s2 (Pounds squared)
Program A
15
17.9
99.7
Program B
15
19.5
95.7
Program C
15
10.2
99.7
Program D
15
22.1
100.6
The physician selects a significance level of a = 0.05. Why should she perform an analysis of variance (ANOVA) with a = 0.05 instead of simply using
multiple t tests with a = 0.05 to compare the six pairs of group means?
An ANOVA avoids the problem of an inflated experimentwise alpha level.
An ANOVA avoids the problem of an inflated testwise alpha level.
The probability of a Type I error when performing multiple t tests at a = 0.05 will be less than 0.05.
O Multiple t tests at a = 0.05 result in an experimentwise alpha level smaller than a = 0.05.
Transcribed Image Text:"The US Centers for Disease Control and Prevention said about 72 million Americans-nearly one out of every four of the country's 304 million residents-are considered obese. Millions more are designated as overweight." The American trend toward obesity has prompted many physicians to offer weight-loss programs to their patients. [Source: Price, w. T. "Physicians Get into the Weight-Loss Business." Florida Today, July 7, 2008.] A physician conducted an experimental study to compare the effectiveness of four different weight-loss programs. In the study, 60 obese adults were randomly assigned to the four programs so that each program had 15 adults. The programs lasted for six months. The weights of the subjects were measured before and after the programs, and each subject's weight loss was computed in pounds. The following table summarizes the results of the study, giving the number of observations and the sample mean and variance of the subjects' weight loss in each program. Treatment Number of Observations, n Sample Mean, M (Pounds) Sample Variance, s2 (Pounds squared) Program A 15 17.9 99.7 Program B 15 19.5 95.7 Program C 15 10.2 99.7 Program D 15 22.1 100.6 The physician selects a significance level of a = 0.05. Why should she perform an analysis of variance (ANOVA) with a = 0.05 instead of simply using multiple t tests with a = 0.05 to compare the six pairs of group means? An ANOVA avoids the problem of an inflated experimentwise alpha level. An ANOVA avoids the problem of an inflated testwise alpha level. The probability of a Type I error when performing multiple t tests at a = 0.05 will be less than 0.05. O Multiple t tests at a = 0.05 result in an experimentwise alpha level smaller than a = 0.05.
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