The UV-visible electronic absorbance spectrum of the following azo dye has an absorption maximum at 524 nm. Three Raman excitation wavelengths are available to obtain the spectrum of this molecule; 406 nm, 514 nm and 785 nm. Explain as fully as possible, the differences in the spectra that would be expected using each of these different excitation wavelengths, and why differences occur. State which wavelength would be the most appropriate, justify your answer. NH2 Meo "OMe N-NH Azo dye
Electronic Transitions and Spectroscopy
The term “electronic” connotes electron, and the term “transition” implies transformation. In a molecule, the electrons move from a lower to a higher energy state due to excitation. The two energy states, the ground state and the excited state are the lowest and the highest energy states, respectively. An energy change is observed with this transition, which depicts the various data related to the molecule.
Photoelectron Spectroscopy
Photoelectron spectroscopy (PES) is a part of experimental chemistry. It is a technique used in laboratories that involves projecting intense beams of radiation on a sample element. In response, the element ejects electrons for which the relative energies are measured.
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