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The weight of an energy bar is approximately normally distributed with a mean of 42.80 grams with a standard deviation of 0.035 gram. Complete parts (a) through (e) below. b. If a sample of 4 energy bars is selected, what is the probability that the sample mean weight is less than 42.775 grams? 0.077 (Round to three decimal places as needed.) c. If a sample of 25 energy bars is selected, what is the probability that the sample mean weight is less than 42.775 grams? (Round to three decimal places as needed.)

The weight of an energy bar is approximately normally distributed with a mean of 42.80 grams with a standard deviation of 0.035 gram. Complete parts (a) through (e) below. b. If a sample of 4 energy bars is selected, what is the probability that the sample mean weight is less than 42.775 grams? 0.077 (Round to three decimal places as needed.) c. If a sample of 25 energy bars is selected, what is the probability that the sample mean weight is less than 42.775 grams? (Round to three decimal places as needed.)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The weight of an energy bar is approximately normally distributed with a mean of 42.80 grams with a standard deviation of 0.035 gram. Complete parts (a) through (e) below. b. If a sample of 4 energy bars is selected, what is the probability that the sample mean weight less than 42.775 grams? 0.077 (Round to three decimal places as needed.) c. If a sample of 25 energy bars is selected, what is the probability that the sample mean weight is less than 42.775 grams? (Round to three decimal places as needed.) d. Explain the difference in the results of (a) and (c). Part (a) refers to an individual bar, which can be thought of as a sample with sample size. Therefore, the standard eror of the mean for an individual bar is times the standard error of the sample in (c) with sample size 25. This leads to a probability in part (a) that is the probability in part (c). (Type integers or decimals. Do not round.) e. Explain the difference in the results of (b) and (c). smaller than the mean Ior the standard rleviation af thA samnlinn distrihutinn) in ie) is i V than in (h) As the etanda The samnle size in (c) is areater than the samnie size in (h) () More larger than the same as View instructor tip P Type here to search
Transcribed Image Text:The weight of an energy bar is approximately normally distributed with a mean of 42.80 grams with a standard deviation of 0.035 gram. Complete parts (a) through (e) below. b. If a sample of 4 energy bars is selected, what is the probability that the sample mean weight less than 42.775 grams? 0.077 (Round to three decimal places as needed.) c. If a sample of 25 energy bars is selected, what is the probability that the sample mean weight is less than 42.775 grams? (Round to three decimal places as needed.) d. Explain the difference in the results of (a) and (c). Part (a) refers to an individual bar, which can be thought of as a sample with sample size. Therefore, the standard eror of the mean for an individual bar is times the standard error of the sample in (c) with sample size 25. This leads to a probability in part (a) that is the probability in part (c). (Type integers or decimals. Do not round.) e. Explain the difference in the results of (b) and (c). smaller than the mean Ior the standard rleviation af thA samnlinn distrihutinn) in ie) is i V than in (h) As the etanda The samnle size in (c) is areater than the samnie size in (h) () More larger than the same as View instructor tip P Type here to search
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