This is a classic data set on wing coloration in the scarlet tiger moth (Panaxia dominula). Coloration in this species had been previously shown to behave as a single-locus, two-allele system with incomplete dominance. Data for 1612 individuals are given below: White-spotted (AA) =1469 Intermediate (Aa) = 138 Little spotting (aa) =5 Calculate the allele frequencies (p and q )

This is a classic data set on wing coloration in the scarlet tiger moth (Panaxia dominula). Coloration in this species had been previously shown to behave as a single-locus, two-allele system with incomplete dominance. Data for 1612 individuals are given below: White-spotted (AA) =1469 Intermediate (Aa) = 138 Little spotting (aa) =5 Calculate the allele frequencies (p and q )

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter19: Population Genetics And Human Evolution

Section: Chapter Questions

Problem 9QP: Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic...

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This is a classic data set on wing coloration in the scarlet tiger moth (Panaxia dominula). Coloration in this species had been previously shown to behave as a single-locus, two-allele system with incomplete dominance. Data for 1612 individuals are given below: White-spotted (AA) =1469 Intermediate (Aa) = 138 Little spotting (aa) =5 Calculate the following frequencies: A=, a=, AA=, Aa=, aa=
A classic dataset on wing coloration in the scarlet tiger moth (Paneaxia dominula) shows that coloration in this species is from a single-locus, two-allele system with incomplete dominance. Data for 1715 tiger moths is given: White-spotted WW 1535 Intermediate spots Ww 168 Little spotting ww 12 What are the wing coloration allele frequencies of the scarlet tiger moth? What are the genotypic frequencies?
Snow geese (Chen caerulescens) come in two color types, white “snows” and “blues” with dark bodies. A single gene controls coloration, where the dark (“blue”) allele (D) is dominant. Another flock of geese is determined to have observed and expected numbers of individuals recorded in the table below. Observed Expected DD 392 303.78 Dd 155 327.15 dd 172 88.08 Determine whether the flock is in Hardy-Weinberg equilibrium by performing a chi-square test. Show all of your work. Use the following table to determine the critical value to which you’ll compare your calculation of the chi-square statistic. Degrees of freedom P = 0.05 1 3.841 2 5.991 3 7.815
Orange coat color in cats is due to an X-linked allele (XO) that iscodominant with the allele for black (X+). When genotypes at the orangelocus were determined for a sample of cats in Minneapolis and St. Paul,Minnesota, the following data were obtained:XOXO females 11XOX+ females 70X+X+ females 94XOY males 36X+Y males 112Calculate the frequencies of the XO and X+ alleles for this population.
The ability to taste the compound PTC is controlled by a dominant allele T, while individuals homozygous for the recessive allele (t) cannot taste PTC. In a population consisting of 500 individuals, 347 are tasters and 153 are non-PTC tasters. Calculate the frequency of the T and t alleles in this population, and frequency of the genotypes. (Please train yourself to use the Hardy-Weinberg equation.) To present your answers, follow the format in the picture below.
A population of sea cucumbers from the maldives has the following allele frequencies for the tentacle colour gene; A= 0.7 and a=0.3. Using Hardy Weinberg equations and these allele frequencies, what are the expected genotype frequencies in the population?
Snow geese (Chen caerulescens) come in two color types, white “snows” and “blues” with dark bodies. A single gene controls coloration, where the dark (“blue”) allele (D) is dominant. Researchers using genetic testing are able to determine the following numbers of individuals of each genotype in another population of geese: DD = 10576, Dd = 14503, dd = 4922. -According to the Hardy-Weinberg equilibrium, what is the expected number of individuals of genotype DD? -Calculate the chi-square statistic from these data. What is the value of the chi-square statistic?
The ability to taste the compound PTC is controlled by a dominant allele T, while individuals homozygous for the recessive allele (t) cannot taste PTC. In a population consisting of 500 individuals, 347 are tasters and 153 are non-PTC tasters. Calculate the frequency of the T and t alleles in this population, and frequency of the genotypes. (Please train yourself to use the Hardy-Weinberg equation.)
ln a population of turtles, there are yellow-green shells and green shells. The yellow shells are caused by a homozygous recessive gene and the green shells are caused by the dominant gene. Given the following data:AA = 340Aa = 270aa = 120 a) Calculate p and q. b) Use a chi square test to determine if these alleles are in Hardy-Weinberg equilibrium. Submit your answer as a pdf or doc file. Show your work
A total of 6129 North American Caucasians were blood typed for theMN locus, which is determined by two codominant alleles, LM and LN.The following data were obtained:Blood type NumberM 1787MN 3039N 1303Use a chi-square test to determine whether this population is in Hardy–Weinberg equilibrium at the MN locus.
You are studying a population of giraffes. In this population, one gene (G) controls spot color in giraffes, which shows incomplete dominance. Individuals with white spots are homozygous gg, individuals with brown spots are homozygous GG, and heterozygotes have orange spots (Gg). You observe 25 white-spotted giraffes, 15 orange-spotted giraffes, and 22 brown-spotted giraffes. Calculate the observed allele frequencies, using p for the frequency of allele G, and the expected number of giraffes of each phenotype assuming Hardy-Weinberg Equilibrium (do not do the entire chi-square calculation!). For frequencies, report four positions after the decimal. For expected numbers, report two positions after the decimal. p = q = Expected number of orange-spotted = Expected number of brown-spotted = Expected number of white-spotted =
The frequency of the A allele is represented by p, while the a allele is represented by q. At hardy-weinburg equilibrium, what is the frequency of the Aa genotype?