Time Which is correct regarding the concept of the lock-and-key as a theory of enzyme action: O a. Both D- and L-isomers of optically active substrates react ot the same rates. O b. The active site is flexible; the catalytic groups of the enzyme are brought complementary by the substrate. OC. The theory of lock-and-key is sufficient to explain the mechanism of enzyme catalysis. Od. The active site is rigid; the catalytic groups of the enzyme are complementary to the substrate. The oxidation of glucose to CO2 and H20 is highly exergonic: AG = 636 kcal/mole, This is spontaneous, but why is it very slow? a. Few glucose and oxygen molecules have the activation energy at room temperature. b. The formation of six CO2 molecules from one glucose molecule decreases entropy, OC. There is too much CO2 in the air. d. CO2 has higher energy than glucose.

Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN:9781305389892
Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Chapter6: Energy, Enzymes, And Biological Reactions
Section: Chapter Questions
Problem 7TYK: In an enzymatic reaction: a. the enzyme leaves the reaction chemically unchanged. b. if the enzyme...
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Which is correct regarding the concept of the lock-and-key as o theory of enzyme action:
O o. Both D- and L-isomers of optically active substrates react ot the same rates.
Ob. The active site is flexible; the catalytic groups of the enzyme are brought complementary by the substrate.
OC. The theory of lock-and-key is sufficient to explain the mechanism of enzyme catalysis
Od. The active site is rigid; the catalytic groups of the enzyme are complementary to the substrate.
The oxidation of glucose to CO2 and H20 is highly exergonic:AG = -636 kcal/mole. This is spontaneous, but why is it very slow?
O a. Few glucose and oxygen molecules have the activation energy ot room temperature.
O b. The formation of six CO2 molecules from one glucose molecule decreases entropy.
O C. There is too much CO2 in the or.
Od. CO2 has higher energy than glucose.
Transcribed Image Text:Time le Which is correct regarding the concept of the lock-and-key as o theory of enzyme action: O o. Both D- and L-isomers of optically active substrates react ot the same rates. Ob. The active site is flexible; the catalytic groups of the enzyme are brought complementary by the substrate. OC. The theory of lock-and-key is sufficient to explain the mechanism of enzyme catalysis Od. The active site is rigid; the catalytic groups of the enzyme are complementary to the substrate. The oxidation of glucose to CO2 and H20 is highly exergonic:AG = -636 kcal/mole. This is spontaneous, but why is it very slow? O a. Few glucose and oxygen molecules have the activation energy ot room temperature. O b. The formation of six CO2 molecules from one glucose molecule decreases entropy. O C. There is too much CO2 in the or. Od. CO2 has higher energy than glucose.
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